Lesson Example Discussion Quiz: Class Homework |
Quiz Discussion |
Title: Calculus |
Grade: Best-SAT3 Lesson: S6-P1 |
Explanation: Let us discuss a few questions on this topic and review the answers to every question. |
Quiz: Discussion in Class
Problem Id | Problem | Options |
---|---|---|
Steps 1 |
Consider the cubic function \$f(x) = x^3 - 6x^2 + 9x\$. |
A) x = 0 , 1 B) x = 0 , 2 C) x = 0 , 3 D) x = 0 , 4 |
Steps 2 |
Find the values of the constant 'a' that make the function \$f(x) = ax^2 + 3x\$ continuous at x = 2. |
A) Any real number B) a must be positive C) a = - 3 D) a = 0 |
Steps 3 |
Solve the quadratic equation \$2x^2 + x - 4 = 0\$ by completing the square. |
A) \$x = (- 1 + \sqrt(33))/2\$ and \$x = (- 1 - \sqrt(33))/2\$ B) \$x = ( 1 + \sqrt(33))/2\$ and \$x = ( 1 - \sqrt(33))/2\$ C) \$x = ( 1 + \sqrt(33))/4\$ and \$x = ( 1 - \sqrt(33))/4\$ D) \$x = (- 1 + \sqrt(33))/4\$ and \$x = (- 1 - \sqrt(33))/4\$ |
Steps 4 |
Solve the equation: \$(2/x) + (3/(x^2)) = 5\$. |
A) \$ 1, - 5/3\$ B) \$ 1, - 3/5\$ C) 1,- 1 D) None of these above |
Steps 5 |
Solve the equation: \$ (x + 1)/(x - 3) - (3x - 2)/(x + 2) = 2\$. |
A) \$ 2 - \sqrt6,-2 - \sqrt6\$ B) \$- 2 + \sqrt6,-2 - \sqrt6\$ C) \$ -2 + \sqrt6,2 - \sqrt6\$ D) \$ 2 + \sqrt6,2 - \sqrt6\$ |
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