Quiz Discussion

Title: Calculus

Grade: Best-SAT3 Lesson: S6-P1

Explanation: Let us discuss a few questions on this topic and review the answers to every question.

Discussion: Step1 Step2 Step3 Step4 Step5

Quiz: Discussion in Class

Problem Id Problem Options

Steps 1

Consider the cubic function \$f(x) = x^3 - 6x^2 + 9x\$.
Let’s find the x-intercepts of this function.

A) x = 0 , 1

B) x = 0 , 2

C) x = 0 , 3

D) x = 0 , 4

Steps 2

Find the values of the constant 'a' that make the function \$f(x) = ax^2 + 3x\$ continuous at x = 2.

A) Any real number

B) a must be positive

C) a = - 3

D) a = 0

Steps 3

Solve the quadratic equation \$2x^2 + x - 4 = 0\$ by completing the square.

A) \$x = (- 1 + \sqrt(33))/2\$ and \$x = (- 1 - \sqrt(33))/2\$

B) \$x = ( 1 + \sqrt(33))/2\$ and \$x = ( 1 - \sqrt(33))/2\$

C) \$x = ( 1 + \sqrt(33))/4\$ and \$x = ( 1 - \sqrt(33))/4\$

D) \$x = (- 1 + \sqrt(33))/4\$ and \$x = (- 1 - \sqrt(33))/4\$

Steps 4

Solve the equation: \$(2/x) + (3/(x^2)) = 5\$.

A) \$ 1, - 5/3\$

B) \$ 1, - 3/5\$

C) 1,- 1

D) None of these above

Steps 5

Solve the equation: \$ (x + 1)/(x - 3) - (3x - 2)/(x + 2) = 2\$.

A) \$ 2 - \sqrt6,-2 - \sqrt6\$

B) \$- 2 + \sqrt6,-2 - \sqrt6\$

C) \$ -2 + \sqrt6,2 - \sqrt6\$

D) \$ 2 + \sqrt6,2 - \sqrt6\$

Discussion: Step1 Step2 Step3 Step4 Step5


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