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Quiz Discussion

Title: Congruency of triangles (RHS)

Grade: 10-a Lesson: S2-L4

Explanation:

Quiz: Discussion in Class

Problem Id	Question
Steps 1	QP and OP are tangents of the circle with center R and QR = OR, then prove \$\triangle RQP \cong \triangle ROP\$. $1$
Steps 2	V is the mid-point of UW, \$TV \bot UW\$ and TU = TW. Prove \$\triangle TUV \cong \triangle TWV\$. $2$
Steps 3	\$\angleA = \angleC = 90^\circ\$ and AB = CE, then prove \$\triangle ABE \cong \CEB\$. $3$
Steps 4	\$\angleA = \angleD = \angleE = 90^\circ\$, BG = FC = HI and BD = HA = AI = EC = FE. Prove \$\triangle FEC \cong \triangle HAI\$. $4$
Steps 5	If QS = TR and \$\angleS = \angleT = 90^\circ\$, then prove \$\triangle QSR \cong \triangle RTQ\$. $5$

Problem Id

Question

Steps 1

QP and OP are tangents of the circle with center R and QR = OR, then prove \$\triangle RQP \cong \triangle ROP\$.

$1$

V is the mid-point of UW, \$TV \bot UW\$ and TU = TW. Prove \$\triangle TUV \cong \triangle TWV\$.

$2$

\$\angleA = \angleC = 90^\circ\$ and AB = CE, then prove \$\triangle ABE \cong \CEB\$.

$3$

\$\angleA = \angleD = \angleE = 90^\circ\$, BG = FC = HI and BD = HA = AI = EC = FE. Prove \$\triangle FEC \cong \triangle HAI\$.

$4$

If QS = TR and \$\angleS = \angleT = 90^\circ\$, then prove \$\triangle QSR \cong \triangle RTQ\$.

$5$