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Title:

Grade: 10-a Lesson: S2-L4

Explanation:

From the figure we can observe that
$1$

QP and OP are the tangents of the circle with center R and \$\angleQ = \angleO = 90^\circ\$.

Consider \$\triangle RQP\$ and \$\triangle ROP\$.

\begin{align} RP &= RP \tag{Common side} \\ RQ &= RO \tag{Given} \\ \angle RQP &= \angle ROP \\ \end{align}

So, \begin{align} \triangle RQP \cong \triangle ROP \\ \end{align}

Henced proved that \$\triangleRQP\$ \$\cong\$ \$\triangleROP\$ by the RHS congruence rule.