Quiz In Class

Title: Congruency of triangles (RHS)

Grade: 10-a Lesson: S2-L4

Explanation:

Quiz: in Class

Problem Id Question

1

\$\angleB = \angleF\$, then prove \$\triangle CBE \cong \triangle DFI\$.

1

2

If \$\angleA = \angleC = 90^\circ\$, prove \$\triangle BAD \cong \triangle BCE\$.

2

3

\$\angleR = \angleP = 90^\circ\$,E is the mid-point of AB, CD and FG and RC = PD. Prove \$\triangle ERC \cong \EPD\$.

3

4

\$\angleD = \angleB = 90^\circ\$. Then \$\triangle CDA \cong \triangle CBA\$.

4

5

AC is the diagonal of the rectangle ABCD and \$\angleB = \angleD = \angleA = \angleC = 90^\circ\$ then prove \$\triangle ABC \cong \triangle ADC\$.

5


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