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Step-5

Title:

Grade: 10-a Lesson: S2-L4

Explanation:

We have to prove that \$\triangle QSR\$ and \$\triangle RTQ\$ are congruent.
$5$

Consider \$\triangle QSR\$ and \$\triangle RTQ\$.

\begin{align} SQ &= TR \tag{Given} \\ RQ &= QR \tag{Given} \\ \angle QSR &= \angle RTQ = 90^\circ \tag{Given} \\ \end{align}

So, \begin{align} \triangle QSR \cong \triangle RTQ \\ \end{align}

Henced proved that \$\triangleQSR\$ \$\cong\$ \$\triangleRTQ\$ by the RHS congruence rule.