Lesson Example Discussion Quiz: Class Homework |
Quiz Discussion |
Title: Synthetic division |
Grade: 8-a Lesson: S1-L4 |
Explanation: Let us discuss a few questions on this topic and review the answers to every question. |
Quiz: Discussion in Class
Problem Id | Problem | Options |
---|---|---|
Steps 1 |
Divide the polynomial \$ 2x^2 - 3x + 1\$ by the binomial \$(x - 1)\$. |
A) Quotient: 2x − 1 with Remainder: 0 B) Quotient: 2x − 5 with Remainder: 4 C) Quotient: 2x − 1 with Remainder: 2 D) Quotient: 2x + 1 with Remainder: -2 |
Steps 2 |
Divide the polynomial \$ 3x^3 - 7x^2 + 6x - 4\$ by the binomial \$(x - 2)\$. |
A) Quotient: \$3x^2 + x - 4\$ with Remainder: -2 B) Quotient: \$3x^2 - x + 4\$ with Remainder: 4 C) Quotient: \$3x^2 - 1 \$ with Remainder: 0 D) Quotient: \$3x^2 - x + 4\$ with Remainder: -4 |
Steps 3 |
Divide the following polynomials using a synthetic division |
A) Quotient \$x^2 - 3x - 5\$ and the remainder is 0 B) Quotient \$x^2 + 3x+ 5\$ and the remainder is 0 C) Quotient \$- x^2 + 3x - 5\$ and the remainder is 0 D) Quotient \$−x^2 + 3x+ 5\$ and the remainder is 0 |
Steps 4 |
Divide the polynomial \$2x^4 + 6x^3 - x^2 - 3x + 6\$ by the binomial \$(x + 3)\$. |
A) Quotient is \$2x^3 + x -1\$ and the remainder is 6 B) Quotient is \$2x^3 - x -1\$ and the remainder is 6 C) Quotient is \$- 2x^3 - x -1\$ and the remainder is 6 D) Quotient is \$- 2x^3 + x +1\$ and the remainder is 6 |
Steps 5 |
Using synthetic division, determine the remainder when the polynomial \$ 2x^5 - 3x^4 + x^3 − 4x^2 + 3x − 1 \$ is divided by the binomial \$x − 2\$. |
A) 7 B) 14 C) 13 D) 6 |
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