Quiz Discussion

Title: Synthetic division

Grade: 8-a Lesson: S1-L4

Explanation: Let us discuss a few questions on this topic and review the answers to every question.

Quiz: Discussion in Class

Problem Id Problem Options

Steps 1

Divide the polynomial \$ 2x^2 - 3x + 1\$ by the binomial \$(x - 1)\$.

A) Quotient: 2x − 1 with Remainder: 0

B) Quotient: 2x − 5 with Remainder: 4

C) Quotient: 2x − 1 with Remainder: 2

D) Quotient: 2x + 1 with Remainder: -2

Steps 2

Divide the polynomial \$ 3x^3 - 7x^2 + 6x - 4\$ by the binomial \$(x - 2)\$.

A) Quotient: \$3x^2 + x - 4\$ with Remainder: -2

B) Quotient: \$3x^2 - x + 4\$ with Remainder: 4

C) Quotient: \$3x^2 - 1 \$ with Remainder: 0

D) Quotient: \$3x^2 - x + 4\$ with Remainder: -4

Steps 3

Divide the following polynomials using a synthetic division
\$(- x^3 + x^2 + 11x +10) / (x + 2)\$.

A) Quotient \$x^2 - 3x - 5\$ and the remainder is 0

B) Quotient \$x^2 + 3x+ 5\$ and the remainder is 0

C) Quotient \$- x^2 + 3x - 5\$ and the remainder is 0

D) Quotient \$−x^2 + 3x+ 5\$ and the remainder is 0

Steps 4

Divide the polynomial \$2x^4 + 6x^3 - x^2 - 3x + 6\$ by the binomial \$(x + 3)\$.

A) Quotient is \$2x^3 + x -1\$ and the remainder is 6

B) Quotient is \$2x^3 - x -1\$ and the remainder is 6

C) Quotient is \$- 2x^3 - x -1\$ and the remainder is 6

D) Quotient is \$- 2x^3 + x +1\$ and the remainder is 6

Steps 5

Using synthetic division, determine the remainder when the polynomial \$ 2x^5 - 3x^4 + x^3 − 4x^2 + 3x − 1 \$ is divided by the binomial \$x − 2\$.

A) 7

B) 14

C) 13

D) 6


Copyright © 2020-2022 saibook.us Contact: info@saibook.us Version: 1.5 Built: 01-May-2024 09:20AM EST