Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: Synthetic division |
Grade: 8-a Lesson: S1-L4 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Divide the polynomial \$ 2x^2 - 3x + 1\$ by the binomial \$(x - 1)\$. |
|
2 |
Step |
The given polynomials are |
\$ 2x^2 - 3x + 1\$ |
3 |
Step |
Identify the coefficients of the polynomial |
2, -3, 1 x - 1 = 0 |
4 |
Step |
Write down the coefficients of the polynomial and the root: |
|
5 |
Step |
Bring down the first coefficient 2 directly under the line |
|
6 |
Step |
Multiply the root 1 by the number you just brought down (2), place this number under the next coefficient (-3), and add to get the new number to bring down |
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7 |
Step |
The numbers on the bottom line after synthetic division are the coefficients of the quotient and the remainder |
|
8 |
Choice.A |
This option matches the correct result obtained from synthetic division. It states that the quotient polynomial is 2x − 1 and there is no remainder |
Quotient: 2x − 1 with Remainder: 0 |
9 |
Choice.B |
This option suggests that the quotient polynomial is 2x − 5 and there is a remainder of 4. However, this is not consistent with the synthetic division result we obtained |
Quotient: 2x − 5 with Remainder: 4 |
10 |
Choice.C |
This option correctly identifies the quotient polynomial as 2x − 1, but it suggests there is a remainder of 2. However, our synthetic division result showed a remainder of 0 |
Quotient: 2x − 1 with Remainder: 2 |
11 |
Choice.D |
This option suggests that the quotient polynomial is 2x + 1 and there is a remainder of -2. Again, this is not consistent with the synthetic division result we obtained |
Quotient: 2x + 1 with Remainder: -2 |
12 |
Answer |
Option |
A |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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