Emily has a right-angled triangle with one side of length 11 inches and the other side of length 18 inches. Calculate the area and perimeter of her triangle.

The given values are

One side length (b) = 11 in

Other side length (h) = 18 in

The area of triangle is

\$A = 1/2 times "base" times "height"\$

Now substitute the values in the area formula

\$A = 1/2 times 11 times 18\$

After simplification

\$ A = 198 /2\$

After simplification

A = 99 sq.in

Perimeter of a triangle (the sum of all three sides)

Perimeter = side 1 + side 2 + hypotenuse

Now substitute the values in the formula

\$c^2 = 11^2 + 18^2\$

After simplification

\$c^2 = 445\$

After simplification

c = 21.09 in [ c = hypotenuse]

Now substitute the values in the perimeter formula

Perimeter = 11 + 18 + 21.09

After simplification

Perimeter = 50.09 in = 50 in

The area and perimeter of her triangle is 99 sq.in and 50 in.

Can you summarize what you’ve understood in the above steps?

This is incorrect because it gives an incorrect perimeter of 52 inches

99 sq.in , 52 in

This is correct because it gives an correct area and perimeter

99 sq.in , 50 in

This is incorrect because it gives an incorrect area of 100 sq.in

100 sq.in , 50 in

This is incorrect because it gives an incorrect area abd perimeter

100 sq.in , 52 in

Option

B

Can you summarize what you’ve understood in the above steps?