Step-2

Title: Area of 2D-Shapes

Grade: 6-a Lesson: S4-L1

Explanation: Let us verify the answer here with the steps.

Lesson Steps Head1

Step Type Explanation Answer

1

Problem

The width of the rectangle is 20 m, and its diagonal is 29 m. Find the area of the rectangle.

2

Step

The given values are

B = 20 m and diagonal = 29 m

3

Formula

Using Pythagorean theorem

\$"Diagonal"^2 = "width"^2 + "length"^2\$

4

Step

Now substitute the values in the formula

\$29^2 = 20^2 + "l"^2\$

5

Step

After simplification

\$841 = 400 + "l"^2\$

6

Step

Now subtract the values

\$"l"^2 = 841 - 400\$

7

Step

After simplification

\$"l"^2 = 441\$

8

Step

After simplification

l = 21 m

9

Formula

Area of rectangle is

\$Area = "length" times "width"\$

10

Step

Now substitute the values in the area formula

\$ "A" = 21 times 20\$

11

Step

After simplification

A = 420 sq.m

12

Step

The area of a triangle is 420 sq.m.

13

SumUp

Can you summarize what you’ve understood in the above steps?

14

Choice.A

This is incorrect. It does not accurately calculates the area by using the formula

240 sq.m

15

Choice.B

This is correct. It accurately calculates the area by using the formula

420 sq.m

16

Choice.C

This is incorrect. It does not accurately calculates the area by using the formula

204 sq.m

17

Choice.D

This is incorrect. It does not accurately calculates the area by using the formula

402 sq.m

18

Answer

Option

B

19

SumUp

Can you summarize what you’ve understood in the above steps?


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