Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: One Variable Data |
Grade: 1400-a Lesson: S4-L1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Data set A consists of the heights of 75 buildings and has a mean of 32 meters. |
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2 |
Step |
Calculate the total height of buildings in data set A: \$"Total height from data set A" = ("Number of buildings in data set A") \times ("Mean height of data set A")\$ \$(75 "buildings") \times (32 "meters")/("building")\$ = 2400 meters |
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3 |
Step |
Calculate the total height of buildings in data set B: \$("Total height from data set B") = ("Number of buildings in data set B") \times ("Mean height of data set B")\$ \$(50 "buildings") \times (62 "meters")/("building")\$ = 3100 meters |
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4 |
Step |
Find the total combined height of data set C: |
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5 |
Step |
Determine the total number of buildings in data set C : 75 buildings + 50 buildings = 125 building. |
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6 |
Step |
Calculate the mean height of data set C : \$(5500)/(125)\$ = 44 meters |
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7 |
Step |
So, the mean height of data set C is 44 meters. |
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8 |
Choice.A |
This option is incorrect because it doesn’t match the calculation we made. The correct mean height for data set C is 44 meters, not 42 meters |
42 |
9 |
Choice.B |
This option is correct. We calculated the mean height of data set C to be 44 meters, which matches this option |
44 |
10 |
Choice.C |
This option suggests a mean height of 49 meters for data set C. However, this value does not match the calculations we performed |
49 |
11 |
Choice.D |
This option proposes that the mean height of data set C is 52 meters. Again, this value is not consistent with our calculations |
52 |
12 |
Answer |
Option |
B |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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