Lesson Example Discussion Quiz: Class Homework |
Quiz At Home |
Title: Trigonometry Identities ( Pythagorean, reciporcal) |
Grade: 1400-a Lesson: S3-L3 |
Explanation: Hello Students, time to practice and review. Let us take next 10-15 minutes to solve the ten problems using the Quiz Sheet. Then submit the quiz to get the score. This is a good exercise to check your understanding of the concepts. |
Quiz: at Home
Problem Id | Problem | Options |
---|---|---|
1 |
If (sec A + tan A - 1) (sec A - tan A + 1) = 3 tan A Which of the following is correct? |
A) \$"LHS" ne "RHS"\$ B) \$"LHS" = "RHS"\$ C) LHS = 0 D) None of the above |
2 |
Use reciprocal identities to simplify |
A) \$("cos"^2("y"))/(2 - "sin"^2("y"))\$ B) \$("cos"^2("y"))/(2 - "cos"^2("y"))\$ C) \$("sin"^2("y"))/(2 - "cos"^2("y"))\$ D) \$("sin"^2("y"))/(2 - "sin"^2("y"))\$ |
3 |
(1 + cos α)(1 + cos β)(1 + cos γ) = (1 – cos α)(1 – cos β)(1 – cos γ) What are the possible values for each member of the equation? |
A) \$1 + "cos"^2(β)"cos"^2(γ)\$ B) \$"cos" α + "cos" β + "cos" γ \$ C) \$"sin" α "sin" β "sin" γ \$ D) 0 |
4 |
Which of the following trigonometric identities is correct? |
A) \$(1/("sec"^2 "x" - "cos"^2 "x")) + ((1)/("cosec"^2 "x" - "sin"^2 x))"sin"^2 "x" . "cos"^2 "x" = ((2 - "sin"^2 "x" "cos"^2 "x")/(1 + "sin"^2 "x" "cos"^2 "x"))\$ B) \$(1/("sec"^2 "x" - "cos"^2 "x")) + ((1)/("cosec"^2 "x" - "sin"^2 "x"))"sin"^2 "x" . "cos"^2 "x" = ((1 - "sin"^4 "x" "cos"^4 "x")/(2 + "sin"^4 "x" "cos"^4 "x"))\$ C) \$(1/("sec"^2 "x" - "cos"^2 "x")) + ((1)/("cosec"^2 "x" - "sin"^2 "x"))"sin"^2 "x" . "cos"^2 "x" = ((1 - "sin"^4 "x" "cos"^4 "x")/(1 + "sin"^4 "x" "cos"^4 "x"))\$ D) \$(1/("sec"^2 "x" - "cos"^2 "x")) + ((1)/("cosec"^2 "x" - "sin"^2 "x"))"sin"^2 "x" . "cos"^2 "x" = ((1 - "sin"^2 "x" "cos"^2 "x")/(2 + "sin"^2 "x" "cos"^2 "x"))\$ |
5 |
Prove the identity: sin(2x)sin(3x)sin(5y) = \$(1/4) "sin"(10"x") − "sin"(8"x") − "sin"(6"x") + "sin"(4"x")\$. |
A) LHS = 0 B) \$"LHS" > "RHS"\$ C) \$"LHS" = "RHS"\$ D) \$"LHS" ne "RHS"\$ |
6 |
Given that csc(β) = 2 and sec(β) = 3, find the values of sin(2β) and cos(2β) using reciprocal identities. |
A) \$ (1/6), (- 4/39)\$ B) \$ (1/5), (- 5/36)\$ C) \$ (1/3), (- 5/36)\$ D) \$ (1/3), (- 1/36)\$ |
7 |
Given the Pythagorean Identity: \$ "sin"^2("x") + "cos"^2("x") = 1 \$, prove the Double Angle Identity for Cosine: \$ "cos"(2"x") = "cos"^2("x") − "sin"^2("x") \$. |
A) Not Proved B) Proved C) Inconclusive D) Infinity |
8 |
"Simplify the following expression: \$ ("cot"^2(θ) - "csc"^2(θ))/ (1 + "cot"(θ)"tan"(θ)) \$ |
A) \$ -1/2 \$ B) \$ 4/3 \$ C) \$ 2/3 \$ D) \$ 1/2 \$ |
9 |
Solve the equation: |
A) \$ (3sqrt2)/4 \$ B) \$ (3sqrt2)/2 \$ C) \$ (9sqrt4)/4 \$ D) \$ (5sqrt3)/3 \$ |
10 |
Prove the identity: |
A) Not Proved B) Infinity C) Proved D) Inconclusive |
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