Quiz Discussion

Title: Inverse Trigonometric Functions

Grade: 1300-a Lesson: S3-L8

Explanation: Let us discuss a few questions on this topic and review the answers to every question.

Quiz: Discussion in Class

Problem Id Problem Options

Steps 1

Solve for x: \$2 "tan"^-1("x") = π/3\$.

A) \$-(\sqrt(3)/3)\$

B) \$(1/\sqrt(3))\$

C) \$(\sqrt(3)/3)\$

D) \$-1/(\sqrt(3))\$

Steps 2

Simplify the following inverse trigonomery function: \$\arc "cos" ("x") + \arc "cos"("y")\$.

A) \$"cos"^-1("xy" - \sqrt(1 - "x"^2)). \sqrt(1 - "y"^2)\$

B) \$"cos"^-1("xy" + \sqrt(1 + "x"^2)). \sqrt(1 + "y"^2)\$

C) \$"cos"^-1("xy" + \sqrt(1 + "x"^2)). \sqrt(1 - "y"^2)\$

D) \$"cos"^-1("xy" - \sqrt(1 - "x"^2)). \sqrt(1 - "y"^2)\$

Steps 3

Prove that \$4 (2 "tan"^-1(1/3) + "tan"^-1 (1/7)) = (pi)\$.

A) 1

B) Proved

C) Zero

D) Not proved

Steps 4

Simplify the following inverse trigonometry function:
\$"cos"^-1("x") + "cos"^-1("y") + "cos"^-1("z") = (pi)\$.

A) \$"x"^2 + "y"^2 - "z"^2 + 2"xyz" = 1\$

B) \$"x"^2 - "y"^2 + "z"^2 - 2"xyz" = 1\$

C) \$"x"^2 - "y"^2 + "z"^2 - 2"xyz" = - 1\$

D) \$"x"^2 + "y"^2 + "z"^2 + 2"xyz" = 1\$

Steps 5

A 12-meter tall building casts a 16-meter long shadow on level ground. Find the angle, in degrees, that the sun makes with the ground (use the appropriate inverse trigonometric function).

A) 30.96 degrees

B) 45 degrees

C) 36.87 degrees

D) 60 degrees


Copyright © 2020-2022 saibook.us Contact: info@saibook.us Version: 1.5 Built: 04-June-2024 09:20AM EST