Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: Inverse Trigonometric Functions |
Grade: 1300-a Lesson: S3-L8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Solve for x: \$2 "tan"^-1("x") = π/3\$. |
|
2 |
Step |
The given equation |
\$2 "tan"^-1("x") = π/3\$ |
3 |
Step |
Divide both sides by 2: |
\$(2/2)"tan"^-1("x") = (π/3)/2\$ \$tan^-1("x") = π/6\$ |
4 |
Step |
Apply the tangent function to both sides to cancel out the inverse tangent: |
\$"tan"("tan"^-1("x")) = "tan"(π/6)\$ |
5 |
Step |
Use the property of inverse and regular tangent functions: |
\$("x") = "tan"(π/6)\$ |
6 |
Step |
Find the value of \$"tan"(π/6)\$: |
\$"tan"(π/6) = (\sqrt(3)/3)\$ |
7 |
Step |
So, the solution for x is \$(\sqrt(3)/3)\$. |
|
8 |
Choice.A |
This is the negative value of the correct solution. In the context of the given equation, it’s not a valid solution |
\$-(\sqrt(3)/3)\$ |
9 |
Choice.B |
This option is the reciprocal of the correct solution. However, the correct solution is \$(\sqrt(3)/3)\$ |
\$(1/\sqrt(3))\$ |
10 |
Choice.C |
This is the correct solution obtained by solving the equation \$2 tan^-1(x) = π/3\$ |
\$(\sqrt(3)/3)\$ |
11 |
Choice.D |
This is incorrect. It’s the negative of the reciprocal of the correct solution |
\$-1/(\sqrt(3))\$ |
12 |
Answer |
Option |
C |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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