Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Slopes & Lines |
Grade: 1400-a Lesson: S3-L4 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Find the length of the line segment between points P(8,5) and Q(4,3). |
|
2 |
Step |
Let us the given points (x1 , y1) & (x2 , y2) |
(8 , 5) & (4 , 3) |
3 |
Formula: |
To find the length of the line segment between two points, you can use the distance formula |
\$"d" = \sqrt ((x2-x1)^2 + (y2 - y1)^2)\$ |
4 |
Step |
Substitute the values into the distance formula |
\$"d" = \sqrt ((4 - 8)^2 + (3 - 5)^2)\$ \$"d" = \sqrt ((-4)^2 + (-2)^2)\$ |
5 |
Step |
Solve for d |
\$"d" = \sqrt(16 + 4)\$ \$"d" = \sqrt (20)\$ |
6 |
Step |
So, the length of the line segment between points (8, 5) and (4, 3) is \$\sqrt (20)\$. |
|
7 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
8 |
Choice.A |
It is correct because it accurately represents the length of the line segment between points P and Q |
\$\sqrt 20\$ |
9 |
Choice.B |
This is the incorrect answer. The distance we calculated is \$\sqrt(20)\$, \$\sqrt 2\$ |
\$\sqrt 2\$ |
10 |
Choice.C |
This is the incorrect answer. The distance we calculated is \$\sqrt(20)\$, \$\sqrt 11\$ |
\$\sqrt 11\$ |
11 |
Choice.D |
This is the incorrect answer. The distance we calculated is \$\sqrt(20)\$, \$\sqrt 12\$ |
\$\sqrt 12\$ |
12 |
Answer |
Option |
A |
13 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
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