Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: Slopes & Lines |
Grade: 1400-a Lesson: S3-L4 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Find the equation of the line passing through the points P(4,3) and Q(2,-1). |
|
2 |
Formula: |
We can use the point-slope form of a linear equation |
y - y1 = m(x - x1) |
3 |
Formula: |
First, let’s find the slope (m) using the two given points |
m = \$(y2 - y1) / (x2 - x1)\$m |
4 |
Step |
Substitute the values into the slope formula and calculate the m |
m = \$(-1 - 3) / (2 - 4)\$ m = \$(-4)/(-2)\$ m = \$2\$ |
5 |
Hint |
Now that we have the slope (m = 2) and one of the points (P) (x1 = 4, y1 = 3) we can use the point-slope form to write the equation |
y - y1 = m(x - x1) |
6 |
Step |
Substitute the values and simplify the equation |
y - 3 = 2(x - 4)
y - 3 = 2x - 8 |
7 |
Step |
Solve for y |
y = 2x - 8 + 3 y = 2x - 5 |
8 |
Step |
So, the equation of the line passing through points P(4, 3) and Q(2, -1) is y = 2x - 5 |
|
9 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
10 |
Choice.A |
Incorrect, the constant term should be negative (-5), not positive (+5) |
y = 2x + 5 |
11 |
Choice.B |
Correct, as explained above |
y = 2x - 5 |
12 |
Choice.C |
Incorrect, it is missing the constant term (-5) |
y = 2x |
13 |
Choice.D |
Incorrect, it is missing the slope term (2x) |
y = 5 |
14 |
Answer |
Option |
B |
15 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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