Lesson Topics Discussion Quiz: Class Homework |
Steps-5 |
Title: Trigonometry |
Grade Lesson s5-p1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
If the combined value of A and B is \$π/2\$, find the value of \$(1-sin^2(A)) (1-cos^2(A)) \times (1 + cot^2(B)) (1+ tan^2(B))\$. |
|
2 |
Step |
The given expression |
\$(1- sin^2(A)) (1 - cos^2(A)) \times (1 + cot^2(B)) (1+ tan^2(B))\$ |
3 |
Step |
Combine value A and B is 90° so here A+ B = 90° then A = 90° - B |
|
4 |
Formula |
\$(1+ tan^2(B)) = sec^2(B) \$ and \$1+ cot^2(B) = cosec^2 (B)\$. |
|
5 |
Step |
So here plug the formulas in the given expression: |
\$(1- sin^2(A)) (1-cos^2(A)) \times cosec^2(B) \times sec^2(B)\$ |
6 |
Hint |
\$sin^2(A) = sin^2(90 - B) = cos^2B \$ and \$cos^2A = cos^2(90 - B) = sin^2B\$. |
|
7 |
Step |
So now plug the hint in the above expression: |
\$(1 - cos^2(B)) (1 - sin^2(B)) \times cosec^2(B) \times sec^2(B)\$ |
8 |
Formula |
\$(1- cos^2(B) = sin^2(B)) "and" (1- sin^2(B) = cos^2(B))\$. |
|
9 |
Step |
Now substitute these formulas into the expression: |
\$sin^2(B) cos^2(B) \times 1/ (cos^2(B)) \times 1/ (sin^2(B))\$ = 1 |
10 |
Solution |
So, the value of the given expression is 1. |
|
11 |
Sumup |
Please summarize Problem, Clue, Hint, Formula, Steps and Solution |
|
Choices |
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12 |
Choice-A |
The expression involves squares of trigonometric functions, and squaring doesn’t always result in 2 |
Wrong 2 |
14 |
Choice-B |
The simplified expression should be in a positive value, not a negative value |
Wrong -1 |
15 |
Choice-C |
The expression simplifies to 1, rather than the previously stated -2, which was incorrect |
Wrong -2 |
16 |
Choice-D |
This is correct due to correct calculation by using the formula |
Correct 1 |
17 |
Answer |
Option |
D |
18 |
Sumup |
Please summarize choices |
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