Lesson Topics Discussion Quiz: Class Homework |
Steps-3 |
Title: Trigonometry |
Grade Lesson s5-p1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Evaluate \$(1+ cos\theta -sin^2(\theta))/(sin\theta(1+ cos\theta))\$. |
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2 |
Step |
The given expression \$(1+ cos\theta -sin^2(\theta))/(sin\theta(1+ cos\theta))\$ |
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3 |
Step |
First, simplify the given numerator: \$1+cos(θ) - (1 - cos^2(θ))\$ i.e., \$(sin^2(θ) = 1 - cos^2(θ))\$ \$1+cos(θ) - 1+cos^2(θ)\$ \$cos(θ) + cos^2(θ)\$ |
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4 |
Step |
Now, simplify the denominator sin(θ) + sin(θ)cos(θ) |
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5 |
Step |
Now, plug these simplifications back into the original expression: \$(cos(θ) + cos^2(θ))/((sin(θ)) + sin(θ)cos(θ))\$ |
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6 |
Step |
Now, factor out a common term of cos(θ) from the numerator and sin(θ) from the denominator: \$(cos(θ) (1+cos(θ)))/(sin(θ) (1 + cos(θ)))\$ |
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7 |
Step |
Now, we can cancel out the common term: \$(cos(θ))/(sin(θ))\$ cot(θ) |
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8 |
Solution |
Therefore, the value of the given expression is cot(θ). |
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9 |
Sumup |
Please summarize Problem, Clue, Hint, Formula, Steps and Solution |
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Choices |
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10 |
Choice-A |
Wrong: Because the expression evaluates to positive cot(θ), not negative cot(θ) |
Wrong \$- cot(\theta)\$ |
11 |
Choice-B |
This is wrong because the expression simplifies to cotθ, not tanθ |
Wrong \$tan(\theta)\$ |
12 |
Choice-C |
Option C is correct since it simplifies the cotθ |
Correct \$cot(\theta)\$ |
13 |
Choice-D |
Option D is incorrect; simplifying the expression yields cotangent θ, not negative tangent θ |
Wrong \$- tan(\theta)\$ |
14 |
Answer |
Option |
C |
15 |
Sumup |
Please summarize choices |
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