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Lesson Example Discussion Quiz: Class Homework

Step-1

Title:

Grade: 10-a Lesson: S2-L2

Explanation:

Description: 1

From the figure we can observe that
$d1$

\begin{align} AB ∥ DC \tag{Given}\\ AD ∥ BC \tag{Given}\\ \end{align}

Consider \$\triangle ABC\$ and \$\triangle CDA\$.

\begin{align} AC &= AC \tag{Common side} \\ \angle BAC &= \angle DCA \tag{Alternate interior angles} \\ \angle BCA &= \angle DAC \tag{Alternate interior angles} \\ \end{align}

So, \begin{align} \triangle ABC \cong \triangle CDA \\ \end{align}

Henced proved that \$\triangleABC\$ and \$\cong\$ \$\triangleCDA\$ by the ASA congruence rule.

$d1$

Steps	Statment	Solution
1	Given	From the figure we can observe that
2	Side of triangles	AB ∥ DC and AD ∥ BC
3	Consider angles	\$\triangle ABC \cong \triangle CDA\$
4	Common side	AC = AC
5	Alternate interior angles	\$angle BAC = angle DCA\$ and \$angle BCA = angle DAC\$
6	Congruency	\$\triangle ABC \cong \triangle CDA\$
7	Prove that	Henced proved that \$\triangleABC\$ and \$\cong\$ \$\triangleCDA\$ by the ASA congruence rule.

Steps

Statment

Solution

Given

From the figure we can observe that

Side of triangles

AB ∥ DC and AD ∥ BC

Consider angles

\$\triangle ABC \cong \triangle CDA\$

Common side

AC = AC

Alternate interior angles

\$angle BAC = angle DCA\$ and \$angle BCA = angle DAC\$

Congruency

\$\triangle ABC \cong \triangle CDA\$

Prove that

Henced proved that \$\triangleABC\$ and \$\cong\$ \$\triangleCDA\$ by the ASA congruence rule.