Step-4

Title: Parallel Lines & Transversals

Grade: 10-a Lesson: S1-L5

Explanation:

Step Type Explanation Answer

1

Problem

In a given below figure PQ ∥ ST. Find the value of x.
4

4a

2

Step

Given

\$\angle QPR = 123°\$ and \$\angle TSR = 110°\$

3

Step

Consecutive interior angles

\$\angle QPR + \angle PRx = 180°\$

4

Step

Now substitute the value

123 + \$\angle 1\$ = 180°

5

Step

After simplication

\$\angle 1\$ = 180 - 123 = 57°

6

Step

Again Rx ∥ ST and transversal SR cuts them at S and R respectively

7

Step

Consecutive interior angles

\$\angle TSR + \angle SRx = 180°\$

8

Step

Now substitute the value

110 + \$\angle 2\$ = 180°

9

Step

After simplication

\$\angle 2\$ = 180 - 110 = 70°

10

Step

Now substitute the value \$\angle 1 and \angle 2\$

\$x = \angle 1 + \ angle2 \$ = \$57 + 70\$

11

Step

After simplication

x = 127°

12

Answer

The x value is 127°


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