1

Problem

The perimeter of a rectangle is 24cm , the length of the rectangle is double its width. Find the area of the rectangle.

2

Step

The perimeter of the rectangle is given,(P)

24 cm

3

Step

Length(L) of the rectangle is double its width(W)

L = 2W

4

Formula

Perimeter of the rectangle P = 2(L + W).

5

Step

Substitute the values

24 = 2(2W + W)
⇒ 2(3W)

6

Step

After simplification

24 = 6W

7

Step

Divide 6 on both sides

\$24/6 = (6W)/6\$

8

Step

After simplification

W = 4

9

Step

We need to determine the length of the rectangle.

L = 2W = 2(4) = 8 cm

10

Formula

Area of the rectangle(A) is
\$A = L \times W\$

11

Step

Substitute the values

\$A = 4 \times 8\$ = 32

12

Solution

So, the Area of the rectangle is 32 sq.cm

13

Sumup

Please summarize steps

Choices

14

Choice-A

The rectangle’s area differs from the given option, making it the incorrect choice in this context

Wrong 36 sq.cm

15

Choice-B

The rectangle’s area differs from the given option, making it the incorrect choice in this context

Wrong 28 sq.cm

16

Choice-C

The rectangle’s area differs from the given option, making it the incorrect choice in this context

Wrong 24 sq.cm

17

Choice-D

The correct option corresponds to the area of the rectangle, making it the accurate choice

Correct 32 sq.cm

18

Answer

Option

D

19

Sumup

Please summarize choices