1

Problem

The perimeter of a rectangle is 20 meters, and the length of a rectangle is 7 cm. Find the area of the rectangle.

2

Step

The given perimeter of a rectangle is

20 mtrs

3

Step

The given length of a rectangle is

7 mtrs

4

Formula

The perimeter of rectangle formula is P = 2(L + W).

5

Step

Substitute the values

20 = 2(7 + W)

6

Step

Now, we have to find the width(W) of a rectangle.Divide 2 on both sides of the equation:

\$20/2 = (2(7 + W))/2\$

7

Step

After simplification

10 = 7 + W

8

Step

Subtract 7 on both sides of the equation:

10 - 7 = 7 -7 +w

9

Step

Width of the rectangle is

W = 3 ft

10

Formula

Now,find the area of rectangle by using formula: \$A = L \times W\$

11

Step

Substitute the values into the formula:

\$A = 7 \times 3\$ = 21

12

Solution

So, the area of the rectangle is 21 sq.ft

13

Sumup

Please summarize steps

Choices

14

Choice-A

The rectangle’s area differs from the given option, making it the incorrect choice in this context

Wrong 3sq. meters

15

Choice-B

The rectangle’s area matches the given option, making it the accurate and preferable selection in this context

Correct 21sq. meters

16

Choice-C

The rectangle’s area differs from the given option, making it the incorrect choice in this context

Wrong 22sq. meters

17

Choice-D

The rectangle’s area differs from the given option, making it the incorrect choice in this context

Wrong 4sq. meters

18

Answer

Option

B

19

Sumup

Please summarize choices