Lesson Topics Discussion Quiz: Class Homework |
Steps-5 |
Title: Equations with absolute value |
Grade 7+ Lesson s1-l1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Solve the equation and check the solutions if it’s satisfied or not: \$| x^2 - 4x - 5| = x + 1\$. |
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2 |
Step |
The given |
\$| x^2 - 4x - 5| = x + 1\$ |
3 |
Hint |
Set up two cases based on the definition of absolute value: \$x^2 - 4x - 5 = x + 1\$ or \$x^2 - 4x - 5 = - (x + 1)\$. |
|
4 |
Step |
Solve each case \$x^2 - 4x - 5 = x + 1\$and then move all terms to one side: |
For \$x^2 - 4x - 5 = x+1\$: \$x^2 - 4x - 5 - x -1\$ |
5 |
Step |
Make it simplify |
\$x^2 - 5x - 6 = 0\$ |
6 |
Step |
Factor the quadratic: |
\$x^2 - 6x + 1x - 6 = 0\$ \$x(x - 6) + 1( x - 6) = 0\$ \$(x - 6) (x + 1) = 0\$ x = 6 and x = -1 |
7 |
Step |
Solve each case \$x^2 - 4x - 5 = - (x + 1)\$and then move all terms to one side: |
\$x^2 - 4x - 5 = - x - 1\$ \$x^2 - 4x - 5 + x + 1\$ |
8 |
Step |
Make it simplify |
\$x^2 - 3x - 4 = 0\$ |
9 |
Step |
Factor the quadratic: |
\$x^2 - 4x + x - 4 = 0\$ \$x(x - 4) + 1(x - 4) = 0\$ \$(x - 4) ( x + 1) = 0\$ x = 4 and x = -1 |
10 |
Step |
Check all potential solutions in the original equation: |
For x = 6: \$|6^2 - 4 times 6 - 5\∣ = 6 + 1\$ which simplifies to \$| 7| = 7\$. This is valid For x = 4: \$| 4^2 - 4 times 4 - 5| = 4 + 1\$ which simplifies to \$| - 5| = 5\$. This is valid For x = -1: \$|1^2 - 4 times 1 - 5| = - 1 + 1\$ which simplifies to∣\$|0\∣ = 0\$. This is valid |
11 |
Solution |
Solutions: x = 6, x = - 1, and x = 4 all satisfy the equation \$\∣x^2 - 4x - 5\∣ = x + 1\$. |
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12 |
Sumup |
Please Summarize Problem, Hint, Clue, Formula and Steps |
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Choices |
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13 |
Choice-A |
This is correct: Substituting these values into the equation confirms that the original equation is satisfied |
Correct x = 6, x = - 1 and x = 4 |
14 |
Choice-B |
Substituting these values into the equation doesn’t satisfy the original equation, so Choice B is wrong |
Wrong x = -1, x = 4 and x = - 6 |
15 |
Choice-C |
Substituting these values into the equation doesn’t satisfy the original equation, so there are wrong |
Wrong x = -1, x = - 4 and x = 6 |
16 |
Choice-D |
Substituting these values into the equation doesn’t satisfy the original equation, so option D is wrong |
Wrong x = - 6, x = - 4 and x = - 1 |
17 |
Answer |
Option |
A |
18 |
Sumup |
Please Summarize Choices |
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