Lesson Topics Discussion Quiz: Class Homework |
Steps-4 |
Title: Equations with absolute value |
Grade 7+ Lesson s1-l1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Solve the equation containing absolute value: \$2/3|r + 6 | - 7 = 9\$. |
|
2 |
Step |
The given equation is |
\$2/3|r + 6 | - 7 = 9\$ |
3 |
Step |
Move constant term 7 to left side and then simplify |
\$2/3 | r + 6| = 9 + 7 \$ \$ 2/3 | r + 6| = 16\$ |
4 |
Step |
Multiply both sides by \$3/2\$ to clear the fraction and then simplify it: |
\$ 2/3 times 3/2 | r + 6| = 16 times 3/2\$ \$|r + 6| = \cancel(48)^24 / \cancel(2)\$ \$|r + 6| = 24\$ |
5 |
Formula |
\$\∣a\∣ = b\$ implies a = b or a = −b. |
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6 |
Hint |
Set up two separate equations based on the definition of absolute value: r + 6 = 24 or r + 6 = - 24. |
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7 |
Step |
Solve r + 6 = 24 equation separately and then solve for r value: |
r + 6 = 24 r = 24 - 6 r = 18 |
8 |
Step |
Solve r + 6 = - 24 equation separately and then solve for r value: |
r + 6 = - 24 r = - 24 - 6 r = - 30 |
9 |
Solution |
The solutions to the equation \$2/3|r + 6 | - 7 = 9\$ are: r = 18 and r = - 30. |
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10 |
Sumup |
Please Summarize Problem, Hint, Clue, Formula and Steps |
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Choices |
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11 |
Choice-A |
Substituting these values into the equation doesn’t satisfy the original equation, so they are incorrect |
Wrong r = -18 and r = -30 |
12 |
Choice-B |
Option B lists r = 81 and r = - 30. While r = - 30 is indeed a solution, r = 81 does not satisfy the equation |
Wrong r = 81 and r = -30 |
13 |
Choice-C |
Substituting these values into the equation doesn’t satisfy the original equation, so option C is wrong |
Wrong r = - 81 and r = - 30 |
14 |
Choice-D |
Substituting these values into the equation satisfies the original equation, so they are correct |
Correct r = 18 and r = - 30 |
15 |
Answer |
Option |
D |
16 |
Sumup |
Please Summarize Choices |
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