Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Equation with two radicals |
Grade: 8-b Lesson: S2-L4 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Determine the value of q \$root(4) (5 - 3q + 8q) = root(4)( -5q - 11)\$. |
|
2 |
Step |
The given euqation |
\$root(4) (5 - 3q + 8q) = root(4)( -5q - 11)\$ |
3 |
Step |
First, simplify the expressions inside the fourth roots |
\$root(4) (5 + 5q) = root(4)( -5q - 11)\$ |
4 |
Hint |
Since the fourth roots of two expressions are equal, the expressions themselves must be equal: |
5 + 5q = - 5q - 11 |
5 |
Step |
Combine like terms by moving all terms involving q to one side and the constants to the other: |
5q + 5q = - 11 - 5 10q = - 16 |
6 |
Step |
Solve for q |
\$ q = - \cancel(16) ^ 8 / \cancel(10)^5\$ \$q = - 8/5\$ |
7 |
Step |
Therefore, the solution to the equation \$root(4) (5 - 3q + 8q) = root(4)( -5q - 11)\$ is \$ - 8/5\$. |
|
8 |
Choice.A |
Substitute \$q = - 8/5\$ into the original equations; it satisfies them, proving option A as a valid solution |
\$q = - 8/5\$ |
9 |
Choice.B |
Substituting \$- 5/8\$ into the original equations reveals that it does not satisfy them so it is wrong |
\$q = - 5/8\$ |
10 |
Choice.C |
The sign is incorrect: the correct solution should include a negative sign |
\$q = 8/5\$ |
11 |
Choice.D |
Option D suggests \$q = 5/8\$, which does not satisfy the equation, so it is incorrect |
\$q = 5/8\$ |
12 |
Answer |
Option |
A |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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