Lesson Example Discussion Quiz: Class Homework |
Quiz At Home |
Title: Equation with two radicals |
Grade: 8-b Lesson: S2-L4 |
Explanation: Hello Students, time to practice and review. Let us take next 10-15 minutes to solve the five problems using the Quiz Sheet. Then submit the quiz to get the score. This is a good exercise to check your understanding of the concepts. |
Quiz: at Home
Problem Id | Problem | Options |
---|---|---|
1 |
Simpilfy \$\sqrt(y + 3) + 2\sqrt(y - 1) = 5\$. |
A) \$ y = 2(73 - 10\sqrt(37))\$ B) \$ y = (2(73 - 10\sqrt(37)))/ 5\$ C) \$ y = (2(73 - 10\sqrt(37)))/ 9\$ D) \$ y = (3(37 + 10\sqrt(37)))/ 9\$ |
2 |
Solve the following radical equation \$\sqrt(r + 5) * \sqrt(r - 2) = 3\$. |
A) \$ r = (-3 + \sqrt(58) )/2\$ B) \$ r = (3 + \sqrt(28) )/2\$ C) \$ r = (-3 + \sqrt(59) )/2\$ D) \$ r = (- 3 + \sqrt(85) )/2 \$ |
3 |
Find the value of d: \$\sqrt(d + 1)/\sqrt(2d - 4) = 2\$. |
A) \$ d = 7/17\$ B) \$ d = 17/7\$ C) \$ d = 1/17\$ D) \$ d = 17/1\$ |
4 |
Solve the equation \$ sqrt(x^2 + 4x + 4) - sqrt(x^2 - 4x + 4) = 2\$. |
A) x = 1 B) x = 2 C) x = 3 D) x = 4 |
5 |
Solve for z: \$root(3)(3 - z) - 2root(3)(z + 1) = 0\$. |
A) \$ z = - 5/9\$ B) \$ z = - 9/5\$ C) \$ z = - 7/4\$ D) \$ z = - 4/7\$ |
6 |
Solve for the variable in the following equation \$4 root(3)(z) + 6 = 2 root(3)(z) + 14 \$. |
A) z = 44 B) z = 64 C) z = 66 D) z = 46 |
7 |
Determine the value of a: \$ root(4)(a + 7) + root(4)(2a - 2) = 4\$. |
A) a = 6 B) a = 9 C) a = 7 D) a = 10 |
8 |
Solve the following radical equation \$ sqrt(c) + 15 = 21 - 7sqrt(c) \$. |
A) \$c = (16)/9\$ B) \$ c =(13)/9\$ C) \$ c = 9/(16) \$ D) \$c = 9/(13)\$ |
9 |
Simplify the following two radicals \$root(3)(x + 2) = root(3)(5 - x)\$. |
A) \$x = 2/3\$ B) \$x = 2\$ C) \$ x = 3/2 \$ D) \$ x = 3\$ |
10 |
Solve the equation \$ 3 - root(3)(2y) = 9 + 7root(3)(2y)\$. |
A) \$ y = - (128)/27\$ B) \$ y = 27/128\$ C) \$ y = (128)/27\$ D) \$ y = - 27/128\$ |
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