Quiz At Home

Title: Equation with two radicals

Grade: 8-b Lesson: S2-L4

Explanation: Hello Students, time to practice and review. Let us take next 10-15 minutes to solve the five problems using the Quiz Sheet. Then submit the quiz to get the score. This is a good exercise to check your understanding of the concepts.

Quiz: at Home

Problem Id Problem Options

1

Simpilfy \$\sqrt(y + 3) + 2\sqrt(y - 1) = 5\$.

A) \$ y = 2(73 - 10\sqrt(37))\$

B) \$ y = (2(73 - 10\sqrt(37)))/ 5\$

C) \$ y = (2(73 - 10\sqrt(37)))/ 9\$

D) \$ y = (3(37 + 10\sqrt(37)))/ 9\$

2

Solve the following radical equation \$\sqrt(r + 5) * \sqrt(r - 2) = 3\$.

A) \$ r = (-3 + \sqrt(58) )/2\$

B) \$ r = (3 + \sqrt(28) )/2\$

C) \$ r = (-3 + \sqrt(59) )/2\$

D) \$ r = (- 3 + \sqrt(85) )/2 \$

3

Find the value of d: \$\sqrt(d + 1)/\sqrt(2d - 4) = 2\$.

A) \$ d = 7/17\$

B) \$ d = 17/7\$

C) \$ d = 1/17\$

D) \$ d = 17/1\$

4

Solve the equation \$ sqrt(x^2 + 4x + 4) - sqrt(x^2 - 4x + 4) = 2\$.

A) x = 1

B) x = 2

C) x = 3

D) x = 4

5

Solve for z: \$root(3)(3 - z) - 2root(3)(z + 1) = 0\$.

A) \$ z = - 5/9\$

B) \$ z = - 9/5\$

C) \$ z = - 7/4\$

D) \$ z = - 4/7\$

6

Solve for the variable in the following equation \$4 root(3)(z) + 6 = 2 root(3)(z) + 14 \$.

A) z = 44

B) z = 64

C) z = 66

D) z = 46

7

Determine the value of a: \$ root(4)(a + 7) + root(4)(2a - 2) = 4\$.

A) a = 6

B) a = 9

C) a = 7

D) a = 10

8

Solve the following radical equation \$ sqrt(c) + 15 = 21 - 7sqrt(c) \$.

A) \$c = (16)/9\$

B) \$ c =(13)/9\$

C) \$ c = 9/(16) \$

D) \$c = 9/(13)\$

9

Simplify the following two radicals \$root(3)(x + 2) = root(3)(5 - x)\$.

A) \$x = 2/3\$

B) \$x = 2\$

C) \$ x = 3/2 \$

D) \$ x = 3\$

10

Solve the equation \$ 3 - root(3)(2y) = 9 + 7root(3)(2y)\$.

A) \$ y = - (128)/27\$

B) \$ y = 27/128\$

C) \$ y = (128)/27\$

D) \$ y = - 27/128\$


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