Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: Equation with one radical |
Grade: 8-b Lesson: S2-L3 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Solve the equation \$root(3)(2h - 9) - 1 = 2\$. |
|
2 |
Step |
Given equation |
\$root(3)(2h - 9) - 1 = 2\$ |
3 |
Step |
Add 1 to each side |
\$root(3)(2h - 9) - 1 + 1 = 2 + 1\$ |
4 |
Hint |
Cube each side to eliminate the radical |
\$(root(3)(2h - 9) )^3 = 3^3\$ |
5 |
Step |
Simplify |
2h - 9 = 27 |
6 |
Clue |
Add 9 to each side |
2h = 36 |
7 |
Step |
Divide each side by 2 |
h = 18 |
8 |
Step |
Therefore, the solution is h = 18. |
|
9 |
Choice.A |
Substituting h = 12 leads to a cube root of 15. Without solving the cube root, we can’t confirm if it simplifies to a value that fits the equation (2 - 1) |
h = 12 |
10 |
Choice.B |
Substituting h = 14 results in a cube root of 19. Since cube roots of perfect cubes are integers, and 19 isn’t a perfect cube, h = 14 likely isn’t the solution |
h = 14 |
11 |
Choice.C |
Substituting h = 16 yields a cube root of 23. Prime numbers (like 23) don’t have perfect cube roots, making h = 16 a less probable solution |
h = 16 |
12 |
Choice.D |
Substituting h = 18 simplifies the radical to \$3\sqrt3\$. However, this directly contradicts the equation \$(3\sqrt(3) ≠ 2)\$, eliminating h = 18 as a solution |
h = 18 |
13 |
Answer |
Option |
D |
14 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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