Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: Equation with one radical |
Grade: 8-b Lesson: S2-L3 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Solve the equation \$2\sqrt(k + 1) = 4\$. |
|
2 |
Step |
Write the original equation |
\$2\sqrt(k + 1) = 4\$ |
3 |
Step |
Divide each side by 2 |
\$2\sqrt(k + 1) = 4\$ \$\sqrt(k + 1) = 2\$ |
4 |
Hint |
Square each side to eliminate the radical |
\$(\sqrt(k + 1))^2 = 2^2\$ |
5 |
Step |
Simplify |
k + 1 = 4 |
6 |
Step |
Subtract 1 from each side |
k = 3 |
7 |
Step |
Therefore, the solution is k = 3. |
|
8 |
Choice.A |
If we substitute k = 0 in the equation, we get: \$2\sqrt(0 + 1) = 4\$, which simplifies to \$2\sqrt1 = 4\$. This is not true because \$2\sqrt1 = 2\$ and not 4 |
k = 0 |
9 |
Choice.B |
Substitute k = 1: \$2\sqrt(1 + 1) = 4\$, which becomes \$2\sqrt2 = 4\$. This is not true either. While \$\sqrt2\$ is approximately 1.41, \$2\sqrt2\$ is roughly 2.82 and not 4 |
k = 1 |
10 |
Choice.C |
Substitute k = 2: \$2\sqrt(2 + 1) = 4\$, which simplifies to \$2\sqrt3 = 4\$. This is not a true statement. \$\sqrt3\$ is approximately 1.73, so \$2\sqrt3\$ is around 3.46 and not 4 |
k = 2 |
11 |
Choice.D |
Substitute k = 3: \$2\sqrt(3 + 1) = 4\$, which becomes \$2\sqrt4 = 4\$. This is a true statement. \$\sqrt4\$ is 2, so \$2\sqrt4\$ is indeed 4 |
k = 3 |
12 |
Answer |
Option |
D |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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