Step-1

Title: Equation with one radical

Grade: 8-b Lesson: S2-L3

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Discussion: Step1 Step2 Step3 Step4 Step5

Step Type Explanation Answer

1

Problem

Solve the equation \$2\sqrt(k + 1) = 4\$.

2

Step

Write the original equation

\$2\sqrt(k + 1) = 4\$

3

Step

Divide each side by 2

\$2\sqrt(k + 1) = 4\$

\$\sqrt(k + 1) = 2\$

4

Hint

Square each side to eliminate the radical

\$(\sqrt(k + 1))^2 = 2^2\$

5

Step

Simplify

k + 1 = 4

6

Step

Subtract 1 from each side

k = 3

7

Step

Therefore, the solution is k = 3.

8

Choice.A

If we substitute k = 0 in the equation, we get: \$2\sqrt(0 + 1) = 4\$, which simplifies to \$2\sqrt1 = 4\$. This is not true because \$2\sqrt1 = 2\$ and not 4

k = 0

9

Choice.B

Substitute k = 1: \$2\sqrt(1 + 1) = 4\$, which becomes \$2\sqrt2 = 4\$. This is not true either. While \$\sqrt2\$ is approximately 1.41, \$2\sqrt2\$ is roughly 2.82 and not 4

k = 1

10

Choice.C

Substitute k = 2: \$2\sqrt(2 + 1) = 4\$, which simplifies to \$2\sqrt3 = 4\$. This is not a true statement. \$\sqrt3\$ is approximately 1.73, so \$2\sqrt3\$ is around 3.46 and not 4

k = 2

11

Choice.D

Substitute k = 3: \$2\sqrt(3 + 1) = 4\$, which becomes \$2\sqrt4 = 4\$. This is a true statement. \$\sqrt4\$ is 2, so \$2\sqrt4\$ is indeed 4

k = 3

12

Answer

Option

D

13

Sumup

Can you summarize what you’ve understood in the above steps?

Discussion: Step1 Step2 Step3 Step4 Step5


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