Solve for x, if \$5/(\sqrt(4 - 3x)) = 1\$.

Given equation

\$5/(\sqrt(4 - 3x)) = 1\$

Multiply both sides of the equation by \$\sqrt(4 - 3x)\$ to eliminate the fraction:

\$5/(\sqrt(4 - 3x)) \times \sqrt(4 - 3x) = 1 \times \sqrt(4 - 3x)\$

\$5 = \sqrt(4 - 3x)\$

Eliminate the Square Root by Squaring Both Sides:

\$5^2 = (\sqrt(4 - 3x))^2\$

25 = 4 - 3x

Subtract 4 from both sides and Divide both sides by -3:

25 - 4 = -3x

21 = -3x

\$x = 21/-3\$

x = -7

Substitute x =-7 back into the original equation to check if it satisfies the equation:

\$5/\sqrt(4 - 3(-7)) = 1\$

Simplify inside the square root:

\$5/\sqrt(4 + 21) = 1\$

\$5/\sqrt(25) = 1\$

1 = 1

Since the left side equals the right side, the solution x = -7 is correct.

This option is not a solution because substituting it into the equation does not make the left-hand side equal to the right-hand side of \$5/(\sqrt(4 - 3x)) = 1\$

-2

This option is not a solution because substituting it into the equation \$5/(\sqrt(4 - 3x)) = 1\$ does not satisfy the equation

-6

This option does not satisfy the equation \$5/(\sqrt(4 - 3x)) = 1\$ when substituted into the equation

-4

This option is the correct solution because substituting it into the equation satisfies the equation \$5/(\sqrt(4 - 3x)) = 1\$

-7

Option

D

Can you summarize what you’ve understood in the above steps?