Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: Solving Equations with Radicals |
Grade: 8-b Lesson: S2-L2 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Solve \$\sqrt(x) - 2 = 3\$. |
|
2 |
Step |
To isolate the square root term, we must move the −2 to the other side of the equation Add 2 to both sides to isolate the square root: |
\$\sqrt(x) - 2 + 2 = 3 + 2\$ |
3 |
Step |
Simplify: |
\$\sqrt(x) = 5\$ |
4 |
Step |
Square Both Sides to Eliminate the Square Root |
\$(\sqrt(x))^2 = 5^2\$ x = 25 |
5 |
Step |
Substitute x=25 back into the original equation to verify that it satisfies the equation |
\$\sqrt(25) - 2 = 3\$ 5 - 2 = 3 |
6 |
Step |
The solution to the equation \$\sqrt(x) - 2 = 3 \$ is x = 25. |
|
7 |
Choice.A |
7 is not a solution because substituting 7 into the equation results \$\sqrt7 - 2 ne 3\$ |
7 |
8 |
Choice.B |
25 is not a solution because substituting 25 into the equation results \$\sqrt25 - 2 = 3\$ |
25 |
9 |
Choice.C |
-25 is not a solution because substituting -25 into the equation results \$\sqrt-25\$ being undefined in the real number system |
-25 |
10 |
Choice.D |
6 is not a solution because substituting 6 into the equation results \$\sqrt6 - 2 ne 3\$ |
6 |
11 |
Answer |
Option |
B |
12 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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