Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Adding and Subtracting Radicals |
Grade: 8-b Lesson: S1-L6 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Simplify the radical expression: \$\sqrt(45) + \sqrt(20) - \sqrt(125)\$. |
|
2 |
Step |
The given radical expression is |
\$\sqrt(45) + \sqrt(20) - \sqrt(125)\$ |
3 |
Step |
Simplify first radical separately: |
\$\sqrt(45) = \sqrt( 9 times 5) = 3\sqrt(5)\$ |
4 |
Step |
Simplify second radical separately: |
\$\sqrt(20) = \sqrt( 4 times 5) = 2 \sqrt(5) \$ |
5 |
Step |
Simplify third radical separately: |
\$\sqrt(125) = \sqrt( 25 times 5) = 5 \sqrt(5)\$ |
6 |
Step |
Substitute the simplified values into the expression: |
\$3\sqrt(5) + 2\sqrt(5) - 5 \sqrt(5)\$ |
7 |
Step |
Simplify the combine like terms: |
\$( 3 + 2 - 5 ) \sqrt(5)\$ \$0\sqrt(5) = 0\$ |
8 |
Step |
Therefore, the simplified form of the expression \$\sqrt(45) + \sqrt(20) - \sqrt(125) \$ is 0. |
|
9 |
Choice.A |
Option A is correct because all the terms with square roots cancel out to zero |
0 |
10 |
Choice.B |
After simplifying, the coefficient of \$\sqrt(5)\$ becomes 0, not 7. Therefore, it is wrong due to this mistake |
\$7\sqrt(5)\$ |
11 |
Choice.C |
Option C is incorrect because it does not match the simplified form we derived, 0 |
\$5\sqrt(7)\$ |
12 |
Choice.D |
Option D is wrong (1) because the expression does not simplify to 1; it simplifies to 0 |
1 |
13 |
Answer |
Option |
A |
14 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
Copyright © 2020-2022 saibook.us Contact: info@saibook.us Version: 1.5 Built: 13-August-2024 09:20AM EST