Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: Adding and Subtracting Radicals |
Grade: 8-b Lesson: S1-L6 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Combine and simplify the following radical expressions: |
|
2 |
Step |
The given radical expression |
\$\sqrt(50)+\sqrt(18)\$ |
3 |
Step |
Simplify first square root separately: |
\$\sqrt(50) = 50 \$ \$50 = 25 times 2 = 5 ^2 times 2\$ \$\sqrt(50) = \sqrt((5^2) times 2)\$ \$\sqrt(50) = 5\sqrt(2)\$ |
4 |
Step |
Simplify second square root separately: |
\$\sqrt(18) = 18 = 2 times 9 = 2 times 3^2\$ \$\sqrt(18) = \sqrt(2 times (3^3))\$ \$\sqrt(18) = 3\sqrt(2)\$ |
5 |
Step |
Combine the simplified expressions: |
\$\sqrt(50)+\sqrt(18)\$ = \$5sqrt(2) + 3\sqrt(2)\$ |
6 |
Step |
Combine like terms: |
\$( 5 + 3) \sqrt(2)\$ \$8\sqrt(2)\$ |
7 |
Step |
Therefore, the simplified form of \$\sqrt(50)+\sqrt(18)\$ is \$8\sqrt(2)\$. |
|
8 |
Choice.A |
\$\sqrt(4) = 2\$, so \$8\sqrt(4)\$ = 8 × 2=16. This is not equivalent to \$8\sqrt(2)\$, so option A is incorrect |
\$8\sqrt(4)\$ |
9 |
Choice.B |
This matches the simplified form we derived, \$8\sqrt(2)\$, but the coefficient is incorrect (it should be 8, not 4). So, option B is incorrect |
\$4\sqrt(2)\$ |
10 |
Choice.C |
This matches the simplified and correct form of the expression \$\sqrt(50)+\sqrt(18)\$. Therefore, option C is correct |
\$8\sqrt(2)\$ |
11 |
Choice.D |
This does not match the simplified form of the given expression, which is \$8\sqrt(2)\$. So, option D is wrong |
\$4\sqrt(3)\$ |
12 |
Answer |
Option |
C |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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