Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Adding and subtracting polynomials |
Grade: 8-b Lesson: S1-L1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Simplify \$(9x^4 y^2 + 6 x^2 - 3y^3 + 24) + (- 15x^2 + 4x^4 y^2 + 8y^3 - 15)\$. |
|
2 |
Step |
Given expressions: |
\$9x^4 y^2 + 6 x^2 - 3y^3 + 24\$, \$- 15x^2 + 4x^4 y^2 + 8y^3 - 15\$ |
3 |
Step |
Combine the terms involving \$x^4 y^2\$: |
\$9x^4 y^2 + 4x^4 y^2\$ \$(9 + 4)x^4 y^2\$ \$13 x^4 y^2\$ |
4 |
Step |
Combine the terms involving \$x^2\$: |
\$6 x^2 - 15 x^2\$ \$(6 - 15) x^2\$ \$-9 x^2\$ |
5 |
Step |
Combine the terms involving \$y^3\$: |
\$-3 y^3 + 8 y^3\$ \$(-3 + 8)y^3\$ \$5 y^3\$ |
6 |
Step |
Combine the constant terms: |
24 - 15 = 9 |
7 |
Step |
Putting it all together, we get: |
\$13(x^4)(y^2) + 5(y^3) - 9(x^2) + 9\$ |
8 |
Step |
So, the simplified expression is \$13(x^4)(y^2) + 5(y^3) - 9(x^2) + 9\$. |
|
9 |
Choice.A |
All terms and their coefficients are correctly placed So, This option matches the given simplified expression perfectly |
\$13(x^4)(y^2) + 5(y^3) - 9(x^2) + 9\$ |
10 |
Choice.B |
This option has incorrect coefficients for \$y^3\$ and the constant term. It should be \$5y^3\$ instead of \$9y^3\$ and 9 instead of 5 |
\$13(x^4)(y^2) + 9(y^3) - 9(x^2) + 5\$ |
11 |
Choice.C |
This option has the incorrect sign for the \$y^3\$ term. It should be \$+5y^3\$ instead of \$−5y^3\$ |
\$13(x^4)(y^2) - 5(y^3) - 9(x^2) + 9\$ |
12 |
Choice.D |
This option has incorrect signs for all terms. The coefficients of \$x^4 y^2\$ and \$y^3\$ have incorrect signs |
\$-13(x^4)(y^2) - 9(y^3) - 9(x^2) - 5\$ |
13 |
Answer |
Option |
A |
14 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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