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Title: Triangles

Grade: 8-a Lesson: S4-L1

Explanation: Let us verify the answer here with the steps.

Description:

Step	Type	Explanation	Answer
1	Problem	Find the area and perimeter of a right angled triangle with sides of lengths 0.9 ft and 1.2 ft.
2	Hint	Formula used	\$"Area" = 1/2 \times ("side")^2\$
3	Step	Let a, b are the sides and h be the hypotenuse.	a = 0.9 ft, b = 1.2 ft,
4	Step	On Simplification	\$"Area" = 1/2 \times ("side")^2\$ \$"Area" = 1/\cancel2^1 \times 0.9 \times \cancel(1.2)^0.6\$ ⇒ \$"Area" = 0.54\$
5	Step	\$"Perimeter" = "side" + "side" + "hypotenuse"\$	Perimeter = \$0.9 + 1.2 + \sqrt((0.9)^2 + (1.2)^2)\$ ⇒ \$2.1 + \sqrt(0.81 + 1.44)\$ ⇒ \$2.1 + \sqrt(2.25)\$ ⇒ \$2.1 + 1.5\$
6	Step	=	Perimeter = \$3.6\$
7	Step	Hence, area and perimeter of a right angled triangle are	\$0.54\$ and \$3.6\$

Step

Type

Explanation

Answer

Problem

Find the area and perimeter of a right angled triangle with sides of lengths 0.9 ft and 1.2 ft.

Hint

Formula used

\$"Area" = 1/2 \times ("side")^2\$

Step

Let a, b are the sides and h be the hypotenuse.

a = 0.9 ft, b = 1.2 ft,

Step

On Simplification

\$"Area" = 1/2 \times ("side")^2\$

\$"Area" = 1/\cancel2^1 \times 0.9 \times \cancel(1.2)^0.6\$

⇒ \$"Area" = 0.54\$

Step

\$"Perimeter" = "side" + "side" + "hypotenuse"\$

Perimeter = \$0.9 + 1.2 + \sqrt((0.9)^2 + (1.2)^2)\$

⇒ \$2.1 + \sqrt(0.81 + 1.44)\$

⇒ \$2.1 + \sqrt(2.25)\$

⇒ \$2.1 + 1.5\$

Step

Perimeter = \$3.6\$

Step

Hence, area and perimeter of a right angled triangle are

\$0.54\$ and \$3.6\$