Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Three-dimensional (3D) shapes |
Grade: 6-a Lesson: S4-L2 |
Explanation: Let us verify the answer here with the steps. |
Lesson Steps Head1
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
A cube-shaped gift box with an open top. Each side of the cube has a length of 16 m. What is the surface area of the open-top gift box? |
|
2 |
Step |
The given values are |
l = 16 m |
3 |
Formula |
Surface Area |
\$"Surface area" = 6 times ("side length")^2\$ |
4 |
Step |
Now, plug these values into the formula |
\$"Surface Area of Cube" = 6 times (16)^2\$ |
5 |
Step |
After simplification |
The surface area of cube = 1536 |
6 |
Formula |
Area of top |
\$"A" = (s)^2\$ |
7 |
Step |
Now, plug these values into the formula |
\$"A" = 16^2\$ |
8 |
Step |
After simplification |
Area of top = 256 sq.cm |
9 |
Step |
Surface Area of Open-Top Gift Box |
Surface Area of Cube - Area of Top |
10 |
Step |
Now, plug these values into the formula |
1536 - 256 = 1280 sq.cm |
11 |
Step |
The surface area of the open-top gift box is 1280 sq.cm. |
|
12 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
13 |
Choice.A |
Incorrect, as it is less than the correct surface area |
1208 sq.cm |
14 |
Choice.B |
Incorrect, as it is greater than the correct surface area |
1820 sq.cm |
15 |
Choice.C |
This option is correct because it accurately calculates the surface area of the open-top gift box with the given dimensions |
1280 sq.cm |
16 |
Choice.D |
Incorrect, as it is less than the correct surface area |
1028 sq.cm |
17 |
Answer |
Option |
C |
18 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
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