Lesson Example Discussion Quiz: Class Homework |
Quiz At Home |
Title: Complex Numbers |
Grade: 1400-a Lesson: S2-L8 |
Explanation: Hello Students, time to practice and review. Let us take next 10-15 minutes to solve the ten problems using the Quiz Sheet. Then submit the quiz to get the score. This is a good exercise to check your understanding of the concepts. |
Quiz: at Home
Problem Id | Problem | Options |
---|---|---|
1 |
Calculate (3+2i)+(5−4i) and (8−3i)−(2+7i). |
A) 7 - 3i and 5 - 11i B) 7 + 3i and 5 + 11i C) 8 - 2i and 6 - 10i D) 7 + 2i and 5 + 11i |
2 |
Convert each number to polar form. \$ (sqrt(2) + i sqrt(2))^8 \$ |
A) 253 B) 254 C) 255 D) 256 |
3 |
Convert \$ 10cis(pi/3) \$ to rectangular form. |
A) \$ 5 + (5i(\sqrt 3)) \$ B) \$ 5 + (5i(\sqrt 3)) \$ C) \$ 5 + (5i(\sqrt 3)) \$ D) \$ 5 + (5i(\sqrt 3)) \$ |
4 |
Find the product of \$ z1 = 12 cis((2pi)/3) \$ and \$ z2 = 10 cis((3pi)/4) \$ |
A) \$ 120 cis((17pi)/12) \$ B) \$ 120 cis((11pi)/12) \$ C) \$ 110 cis((17pi)/12) \$ D) \$ 150 cis((15pi)/12) \$ |
5 |
Given \$ z = 8 - 8i(\sqrt(3)) \$, compute \$ z^2 \$. |
A) \$ -128 - 128i(\sqrt(3)) \$ B) \$ -118 - 128i(\sqrt(3)) \$ C) \$ -128 - 128i(\sqrt(5)) \$ D) \$ -128 - 108i(\sqrt(2)) \$ |
6 |
Suppose \$z = (2 - i)^2 + ((7 - 4i) / (2 + i)) - 8\$, express z in the form of x + iy such that x and y are real numbers. |
A) z = (-2 - 7i) B) z = (-3 - 7i) C) z = (2 + 7i) D) z = (2 - 7i) |
7 |
If \$z_1 = 2 + 8i\$ amd \$z_2 = 1 - i\$, then find \$|z_1 / z_2|\$. |
A) \$\sqrt(4)\$ B) \$\sqrt(34)\$ C) \$\sqrt(30)\$ D) \$\sqrt(44)\$ |
8 |
If \$|z^2 - 1| = |z^2| + 1\$, then show that z lies on an imaginary axis. |
A) Doesn’t exists any axis. B) z lies on the x axis. C) z lies on the y axis. D) z lies on the no axis. |
9 |
Find real x and y if (x - iy) (3 + 5i) is the conjugate of – 6 – 24i. |
A) x = 3 and y = 3 B) x = 2 and y = -2 C) x = 3 and y = -3 D) x = -2 and y = 2 |
10 |
Find the relation between a and b if z = a + ib if \$|(z - 3)/(z + 3)| = 2\$. |
A) \$(a + 5)^2 + (4^2) = (b^2)\$ B) \$(4 + 5)^2 + (a^2) = (b^2)\$ C) \$(a + 5)^2 + (7^2) = (3^2)\$ D) \$(a + 5)^2 + (b^2) = (4^2)\$ |
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