Multiply the complex numbers: \$ (2 + 3i) times (4 - i) \$.

A) 11 + 10i

B) 12 + 8i

C) 9 + 10i

D) 7 - 3i

Solve the equation: \$ z^2 + 6z + 13 = 0\$, where z is a complex number.

A) z = - 3 + 2i and z = 3 + 2i

B) z = 3 + 2i and z = - 3 - 2i

C) z = - 3 + 2i and z = - 3 - 2i

D) z = 3 + 2i and z = 3 - 2i

Divide the complex numbers: \$(6 + 3i) / (2 + i)\$.

A) 3

B) -2

C) 6

D) 0

Find all the complex solutions to the equation: \$z^3 + 8 = 0\$.

A) \$z = 1, z = (-1 \pm i sqrt(3)) \$

B) \$ z = - 2 , z = 1 \pm i\sqrt(3) \$

C) \$z = 2, z = (2 \pm i sqrt(6)) \$

D) \$z = 1, z = (1 \pm i sqrt(2)) \$

Find the square root of the complex number \$z = 1 - 2i\$.

A) \$ sqrt(z) = \pm(sqrt((sqrt(5) + 1)/2) - isqrt((sqrt(5) - 1)/2))\$

B) \$ \sqrtz = ± (\sqrt((2 ± \sqrt5)/2) + i\sqrt((1 ± \sqrt5)/2)) \$

C) \$ sqrt(z) = \pm(sqrt((sqrt(5) + 3)/2) - isqrt((sqrt(5) - 3)/2))\$

D) \$ sqrt(z) = \pm(sqrt((sqrt(2) + 3)/2) + isqrt((sqrt(2) - 3)/2))\$