Lesson Example Discussion Quiz: Class Homework |
Example |
Title: Quadratic equations with rational expression |
Grade: 1300-a Lesson: S2-L3 |
Explanation: The best way to understand SAT-2 is by looking at some examples. Take turns and read each example for easy understanding. |
Examples:
Solve the equation: \$(3/x) + (2/(x + 1)) = 5/(x + 2 ) \$.
Step 1a
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Clear the fractions by finding a common denominator. In this case, the common denominator for the three fractions is \$x(x+1)(x+2)\$. Multiply every term by this the common denominator to eliminate the fractions: \$x(x + 1)(x + 2) ( 3/x + 2/(x + 1) ) = x(x + 1)(x + 2)( 5/(x + 2 )) \$ After simplifying, the equation becomes: \$ 3(x + 1)(x + 2) + 2x(x + 2) = 5x(x + 1) \$. |
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Explanation: Here, we multiply the common denominator for the three fractions, and then after simplification, we get \$ 3(x + 1)(x + 2)+ 2x(x + 2) = 5x(x + 1) \$. |
Step 1b
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Expand and simplify the equation. \$ 3(x^2 + 3x + 2) + 2(x^2 + 2x) = 5x^2 + 5x \$ Expanding and simplifying further, we get: \$ 3x^2 + 9x + 6 + 2x^2+ 4x = 5x^2 + 5x \$ Combining like terms: \$ 5x^2 + 13x + 6 = 5x^2 + 5x \$ |
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Explanation: Here, we simplify the equation then we get \$ 5x^2 + 13x + 6 = 5x^2 + 5x \$. |
Step 1c
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Move all terms to one side of the equation. \$ \cancel(5x^2) + 13x + 6 - \cancel(5x^2) - 5x = 0 \$ Simplifying: \$ 8x + 6 = 0 \$ |
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Explanation: Here, after we simplify the equation then we get a linear equation is \$ 8x + 6 = 0 \$. |
Step 1d
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Solve the resulting linear equation. By subtracting 6 from both sides: \$ 8x + \cancel6 - \cancel6 = 0 - 6 \$ After cancellation : \$ 8x = - 6 \$ Dividing by 8: \$ (\cancel(8)^1x)/\cancel8^1 = - \cancel6^3/\cancel8^4 \$ After cancellation: \$ x = - 3/4 \$ Therefore, the solution to the quadratic equation with rational expression is \$ x = - 3/4 \$. |
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Explanation: Therefore, the solutions to the quadratic equation is \$x = - 3/4 \$. |
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