Lesson Example Discussion Quiz: Class Homework |
Quiz In Class |
Title: Non-linear equations in one variable |
Grade: 1300-a Lesson: S1-L6 |
Explanation: Hello Students, time to practice and review. Let us take next 10-15 minutes to solve the ten problems using the Quiz Sheet. Then submit the quiz to get the score. This is a good exercise to check your understanding of the concepts. |
Quiz: in Class
Problem Id | Problem | Options |
---|---|---|
1 |
Solve the equation \$\sqrt("x" + 3) + \sqrt(3) = 3\$. |
A) 4 B) 1 C) 2 D) 3 |
2 |
If \$ |4"x" - 4| = 112\$, what is the positive value of x - 1? |
A) 25 B) 28 C) 52 D) 82 |
3 |
\$("x" + 2) ("x" + 3) = ("x" - 2) ("x" - 3) + 10\$ |
A) - 1 B) 0 C) 2 D) 1 |
4 |
For the equation \$12"x"^2 + 5"x" - 143 = 0\$, what is one possible value of x? |
A) 5.25 B) 3.52 C) 5.52 D) 3.25 |
5 |
A radioactive substance decays according to the model \$"N"("t") = "N"_0("e")^(− kt)\$, where \$"N"_0\$ is the initial quantity, k is the decay constant, and tt is time. If a sample initially has 500 grams and decays to 200 grams in 3 years, find the decay constant k. |
A) 0.35 B) 0.503 C) 0.305 D) 0.53 |
6 |
Solve the equation \$"x"^4 − 4"x"^3 + 6"x"^2 − 4"x" + 1 = 0\$. |
A) \$x = 1/2\$ B) x = 2 C) x = 1 D) x = 0 |
7 |
\$"x"^2 - "x" - 1 = 0\$ |
A) \$"x" = (1 + \sqrt(5))/2\$ and \$"x" = (1 - \sqrt(5))/2\$ B) x = 1 and x = 2 C) \$"x" = -(1/2)\$ and \$"x" = 3/2\$ D) \$"x" = (-1 + \sqrt(5))/2\$ and \$"x" = (-1 - \sqrt(5))/2\$ |
8 |
(x - 4)(x + 2)(x - 1) = 0 |
A) - 8 B) 3 C) 8 D) - 3 |
9 |
\$(2("x" + 1))/("x" + 5) = 1 - 1/("x" + 5)\$ What is the solution to the equation above? |
A) 0 B) 2 C) 3 D) 5 |
10 |
\$- 4"x"^2 - 7"x" = - 36\$ |
A) \$7/4\$ B) \$9/4\$ C) 4 D) 7 |
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