Lesson Example Discussion Quiz: Class Homework |
Quiz Discussion |
Title: Inverse Trigonometric Functions |
Grade: 10-a Lesson: S3-L8 |
Explanation: Let us discuss a few questions on this topic and review the answers to every question. |
Quiz: Discussion in Class
Problem Id | Problem | Options |
---|---|---|
Steps 1 |
Solve for x: \$2 "tan"^-1("x") = π/3\$. |
A) \$-(\sqrt(3)/3)\$ B) \$(1/\sqrt(3))\$ C) \$(\sqrt(3)/3)\$ D) \$-1/(\sqrt(3))\$ |
Steps 2 |
Simplify the following inverse trigonomery function: \$\arc "cos" ("x") + \arc "cos"("y")\$. |
A) \$"cos"^-1("xy" - \sqrt(1 - "x"^2)). \sqrt(1 - "y"^2)\$ B) \$"cos"^-1("xy" + \sqrt(1 + "x"^2)). \sqrt(1 + "y"^2)\$ C) \$"cos"^-1("xy" + \sqrt(1 + "x"^2)). \sqrt(1 - "y"^2)\$ D) \$"cos"^-1("xy" - \sqrt(1 - "x"^2)). \sqrt(1 - "y"^2)\$ |
Steps 3 |
Prove that \$4 (2 "tan"^-1(1/3) + "tan"^-1 (1/7)) = (pi)\$. |
A) 1 B) Proved C) Zero D) Not proved |
Steps 4 |
Simplify the following inverse trigonometry function: |
A) \$"x"^2 + "y"^2 - "z"^2 + 2"xyz" = 1\$ B) \$"x"^2 - "y"^2 + "z"^2 - 2"xyz" = 1\$ C) \$"x"^2 - "y"^2 + "z"^2 - 2"xyz" = - 1\$ D) \$"x"^2 + "y"^2 + "z"^2 + 2"xyz" = 1\$ |
Steps 5 |
A 12-meter tall building casts a 16-meter long shadow on level ground. Find the angle, in degrees, that the sun makes with the ground (use the appropriate inverse trigonometric function). |
A) 30.96 degrees B) 45 degrees C) 36.87 degrees D) 60 degrees |
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