Quiz At Home

Title: Trigonometry Identities ( Pythagorean, reciporcal)

Grade: 10-a Lesson: S3-L3

Explanation: Hello Students, time to practice and review. Let us take next 10-15 minutes to solve the ten problems using the Quiz Sheet. Then submit the quiz to get the score. This is a good exercise to check your understanding of the concepts.

Quiz: at Home

Problem Id Problem Options

1

If \$"cot" \theta = 3/4\$ and \$"sin"\theta\$ < 0, find \$"csc" \theta\$.

A) \$- 5/4\$

B) \$ 4/5 \$

C) \$ 3/4\$

D) \$- 4/3\$

2

Simplify the following expression \$ ("cot"^2("x")) / ("csc"("x") - "sin"("x"))\$.

A) - sec(x)

B) csc(x)

C) sin(x)

D) - cos(x)

3

Triangle PQR is a right triangle with a 90-degree angle at vertex Q. The length of side PQ is 25 and the length of side QR is 60. Triangle STU is similar to triangle PQR. The vertices S, T, and U correspond to vertices P, Q, and R, respectively. What is the value of cos∠U?

A) \$5/13\$

B) \$5/12\$

C) \$12/13\$

D) \$5/6\$

4

Simplify: \$"sin"^2(x)"tan"^2("x") + "cos"^2(x)\$.

A) \$csc^2(x)- 2cos^2(x)\$

B) \$sec^2(x) + tan^2(x)\$

C) \$csc^2(x) - cot^2(x)\$

D) \$sec^2(x) - 2sin^2(x)\$

5

Find the value of the expression using a reciprocal identity. \$"sin"\theta = -1/2\$ and \$"tan"\theta = \sqrt(3)/3\$, \$"cos"\theta\$.

A) \$\sqrt(2)/3\$

B) \$- \sqrt(3)/2\$

C) \$-\sqrt(2)/3\$

D) \$\sqrt(3)/2\$

6

Simplify: \$ ("sin"(θ) + "cos"(θ))/("sin"(θ) − "cos"(θ)) \$.

A) \$ ( 1 + "sin"2θ)/("cos"2θ) \$

B) \$ ( 1 - "sin"2θ)/("cos"2θ) \$

C) \$ - (( 1 + "sin"2θ))/("cos"2θ) \$

D) \$ - ( (1 - "sin"2θ))/("cos"2θ) \$

7

\$"csc"\theta = ((2\sqrt(3))/3)\$, find \$"sin"\theta\$ using the reciprocal identity.

A) \$2/\sqrt(3)\$

B) \$\sqrt(3)/2\$

C) \$- 2/\sqrt(3)\$

D) \$- 2/\sqrt(2)\$

8

Given that sin(α) = \$3/5\$ and cos(β) = \$4/5 \$ find the exact value of
cos (α - β).

A) 1

B) \$8/5\$

C) 0

D) \$19/21\$

9

Simplify \$ ("sec"("x")"sin"^2("x"))/(1 + "sec"("x")) \$.

A) 1 + cosx

B) - cos(x) + 1

C) 1 - sinx

D) tan(3x) + 1

10

Simplify \$("cscx" + "cotx") (( 1 - "cosx")/("sinx") ) \$.

A) \$ 1/("sinx") \$

B) \$ ("sinx")/("cosx") \$

C) 1

D) \$ 1/"cosx"\$


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