Lesson Example Discussion Quiz: Class Homework |
Quiz In Class |
Title: Calculus |
Grade: 10-a Lesson: S2-L8 |
Explanation: Hello Students, time to practice and review. Let us take next 10-15 minutes to solve the ten problems using the Quiz Sheet. Then submit the quiz to get the score. This is a good exercise to check your understanding of the concepts. |
Quiz: in Class
Problem Id | Problem | Options |
---|---|---|
1 |
Use factoring to solve the equation: |
A) t = 0, t = 3 B) t = - 6, t = 4 C) t = - 3, t = 9 D) t = 2, t = 6 |
2 |
y = r is a root of the given polynomial. Find the other two roots and write the polynomial in fully factored form: \$ f(y) = y^3 - 7y^2 - 6y + 72\$; r = 4 |
A) y = 3, 5, - 2 B) y = 4, 6, - 3 C) y = - 1, 9, - 2 D) y = 2, 0, - 3 |
3 |
Solve the equation: \$(x^2 + 5x + 6)/(x^2 - 9) = (x + 3)/(x - 3)\$. |
A) 1, - 1 B) \$ - 1/3, 1\$ C) No solutions D) \$ 1/2 ,- 3/2\$ |
4 |
Perform the indicated operation and reduce the answer to the lowest terms: \$ (y^2 - 49)/(2y^2 - 3y - 5) \div (y^2 - y - 42)/(y^2 + 7y + 6)\$ |
A) \$ (y + 5)/(2y - 5) \$ B) \$ (y - 3)/(y + 1) \$ C) \$ (3y + 7)/( y - 5) \$ D) \$ (y + 7)/(2y - 5) \$ |
5 |
Determine where the given function is discontinuous |
A) \$ x = - 3 + \sqrt2, x = - 3 + 2\sqrt2, x = - 3 - 2\sqrt2 \$ B) \$ x = 0, x = - 3 + \sqrt2, x = - 3 - \sqrt2 \$ C) \$ x = 2 - \sqrt3, x = 3 + 2\sqrt2, x = 3 - 2\sqrt2 \$ D) \$ x = 0, x = - 3 + 2\sqrt2, x = - 3 - 2\sqrt2 \$ |
6 |
Solve the quadratic equation: \$2 m^2 + 7m - 15 = 0\$ |
A) \$ m=(2/3)\$ and m = 5 B) \$ m=(2/3)\$ and m = -5 C) \$ m=(3/2)\$ and m = -5 D) \$ m=(3/2)\$ and m = 5 |
7 |
Factorize the quadratic expression: \$ 9 x^2 - 6 x + 1 \$ |
A) \$(3 x + 1 )^2\$ B) \$(3 x - 1 )^2\$ C) \$(4 x - 3 )^2\$ D) \$(4 x + 3 )^2\$ |
8 |
Find the y-intercept of the function : r(x) = \$ 2 x^4 - x^3 + 5 x^2 - 8 x + 1 \$ |
A) ( 0, 1 ) B) ( 1, 0 ) C) ( 1, 1 ) D) ( 0, 0 ) |
9 |
solve this equation \$( 2x^2 - 5x + 2 )/(x-2) \$ = 0 |
A) x=2 and x=1 B) x=2 and x=\$1/2\$ C) x=2 and x=\$1/3\$ D) x=2 and x=-1 |
10 |
Find the limit of g(x) = \$ (4x^3 - 3x^2 + 5x - 7) / (2x^2 + x - 1 )\$ as x approaches -1. |
A) 1 B) 2 C) Does not exist D) none of the above |
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