Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Complex Numbers |
Grade: 10-a Lesson: S2-L8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Divide the complex numbers: \$(6 + 3i) / (2 + i)\$ . |
|
2 |
Step |
To divide the complex numbers |
\$(6 + 3i) / (2 + i)\$ |
3 |
Step |
We can use the process of multiplying the numerator and denominator by the conjugate of the denominator. The conjugate of a complex number a + bi is a − bi. |
|
4 |
Step |
To find the conjugate of the denominator (2 + i), simply change the sign of the imaginary part to get 2 - i |
\$(6 + 3i) / (2 + i) times (2 - i) / (2 - i) \$ |
5 |
Step |
Now, perform the multiplication in both the numerator and denominator: |
\$ ( 12 - 6i + 6i - 3i^2 ) / ( 4 - 2i + 2i - i^2) = (12 - 3i^2) / (4 - i^2)\$ |
6 |
Step |
Simplify terms with \$i^2\$ (where \$i^2 = -1\$), then simplify |
\$ ( 12 + 3) / ( 4 + 1 )\$ |
7 |
Step |
So, the result is |
\$ 15/5 = 3 \$ |
8 |
Step |
So, the division of the complex numbers \$(6 + 3i) / (2 + i)\$ is equal to 3. |
|
9 |
Choice.A |
This is the accurate result of the division |
3 |
10 |
Choice.B |
This is wrong. The result of the division is not negative it’s a positive |
-2 |
11 |
Choice.C |
This is not correct because the calculation results in 3, not 6 |
6 |
12 |
Choice.D |
This is incorrect because, as we’ve shown, the division yields a non-zero complex number, specifically 3 |
0 |
13 |
Answer |
Option |
A |
14 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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