Lesson Example Discussion Quiz: Class Homework |
Quiz Discussion |
Title: Quadratic equations with rational expression |
Grade: 10-a Lesson: S2-L3 |
Explanation: Let us discuss a few questions on this topic and review the answers to every question. |
Quiz: Discussion in Class
Problem Id | Problem | Options |
---|---|---|
Steps 1 |
Solve the equation: \$(x^2 + 3x)/(x^2 - 4) - (2x)/(x + 2) = 0\$. |
A) 0,- 4, 5 B) 0,-5, - 1 C) 0,7, - 2 D) 0,2,- 7 |
Steps 2 |
Solve the equation: \$(3x^2 + 4) / (2x) = (x - 1) / 3\$. |
A) \$ (-1 + i\sqrt83) / 7 and (-1 - i\sqrt83) / 7 \$ B) \$ ((2) + \sqrt(-332))/14\$ and \$ ((2) - \sqrt(-332))/14\$ C) \$ ((-2) + \sqrt(-332))/7\$ and \$ ((-2) - \sqrt(-332))/7\$ D) None of these above |
Steps 3 |
Solve the equation: \$(2/x) + (3/(x^2)) = 5\$. |
A) \$ 1, - 5/3\$ B) \$ 1, - 3/5\$ C) 1,- 1 D) None of these above |
Steps 4 |
Solve the equation: \$(x - 1)/(x - 2) + (x - 2)/(x - 1) = 4\$. |
A) \$ (3 + \sqrt3)/2,(3 - \sqrt3)/2\$ B) \$ (3 + \sqrt3)/2,(-3 - \sqrt3)/2\$ C) \$ (-3 - \sqrt3)/2,(3 - \sqrt3)/2\$ D) \$ (-3 + \sqrt3)/2,(-3 - \sqrt3)/2\$ |
Steps 5 |
Solve the equation: \$ (x + 1)/(x - 3) - (3x - 2)/(x + 2) = 2\$. |
A) \$ 2 - \sqrt6,-2 - \sqrt6\$ B) \$- 2 + \sqrt6,-2 - \sqrt6\$ C) \$ -2 + \sqrt6,2 - \sqrt6\$ D) \$ 2 + \sqrt6,2 - \sqrt6\$ |
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