Quiz Discussion

Title: Quadratic equations with rational expression

Grade: 10-a Lesson: S2-L3

Explanation: Let us discuss a few questions on this topic and review the answers to every question.

Quiz: Discussion in Class

Problem Id Problem Options

Steps 1

Solve the equation: \$(x^2 + 3x)/(x^2 - 4) - (2x)/(x + 2) = 0\$.

A) 0,- 4, 5

B) 0,-5, - 1

C) 0,7, - 2

D) 0,2,- 7

Steps 2

Solve the equation: \$(3x^2 + 4) / (2x) = (x - 1) / 3\$.

A) \$ (-1 + i\sqrt83) / 7 and (-1 - i\sqrt83) / 7 \$

B) \$ ((2) + \sqrt(-332))/14\$ and \$ ((2) - \sqrt(-332))/14\$

C) \$ ((-2) + \sqrt(-332))/7\$ and \$ ((-2) - \sqrt(-332))/7\$

D) None of these above

Steps 3

Solve the equation: \$(2/x) + (3/(x^2)) = 5\$.

A) \$ 1, - 5/3\$

B) \$ 1, - 3/5\$

C) 1,- 1

D) None of these above

Steps 4

Solve the equation: \$(x - 1)/(x - 2) + (x - 2)/(x - 1) = 4\$.

A) \$ (3 + \sqrt3)/2,(3 - \sqrt3)/2\$

B) \$ (3 + \sqrt3)/2,(-3 - \sqrt3)/2\$

C) \$ (-3 - \sqrt3)/2,(3 - \sqrt3)/2\$

D) \$ (-3 + \sqrt3)/2,(-3 - \sqrt3)/2\$

Steps 5

Solve the equation: \$ (x + 1)/(x - 3) - (3x - 2)/(x + 2) = 2\$.

A) \$ 2 - \sqrt6,-2 - \sqrt6\$

B) \$- 2 + \sqrt6,-2 - \sqrt6\$

C) \$ -2 + \sqrt6,2 - \sqrt6\$

D) \$ 2 + \sqrt6,2 - \sqrt6\$


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