Step-206

Title: Quadratic-Equations and Factors

Grade: 10-a Lesson: S2-L1

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Solve the quadratic equation: \$4x^2 + 8x + 14 = 0\$.

2

Step

Simplify the equation

\$2(2x^2 + 4x + 7) = 0\$

\$2x^2 + 4x + 7 = 0\$

3

Formula:

To solve the quadratic equation \$2x^2 + 4x + 7 = 0\$, we can use the quadratic formula. The quadratic formula states that for an equation in the form \$ax^2 + bx + c = 0\$, the solutions for x can be found using the formula

\$x = (-b ± \sqrt (b^2 - 4ac)) / (2a)\$

4

Hint

For the equation \$2x^2 + 4x + 7 = 0\$ then, substituting these values into the quadratic formula, we get

a = 2, b = 4, and c = 7

\$x = (- 4 ± \sqrt (4^2 - 4 times 2 times 7)) / (2 times 2)\$

\$x = (- 4 ± \sqrt (- 40)) / 4\$

5

Step

After simplification

\$x = (- 4 ± \sqrt (2^2 i^2 5)) / 4\$

\$x = (- 4 ± 2i \sqrt 5) / 4\$

\$x = (- 2 ± i \sqrt 5) / 2\$

6

Step

This gives us two possible solutions

\$x_1 = (- 2 + i \sqrt 5) / 2\$ and \$x_2 = (- 2 - i \sqrt 5) / 2 \$

7

Answer

Option

A


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