Quiz Discussion

Title: Linear inequalities in one or two variables

Grade: 10-a Lesson: S1-L4

Explanation: Let us discuss a few questions on this topic and review the answers to every question.

Quiz: Discussion in Class

Problem Id Problem Options

Steps 1

Solve the inequality: 3x + 5 > 10.

A) \$ x > 3/5\$

B) \$ x > 5/3\$

C) \$ x < 5/3\$

D) \$ x < 3/5\$

Steps 2

Solve the following inequality: \$ 4x + 2y ge 6x - 3y + 2 \$.

A) \$ y ge (2x + 2) / 5 \$

B) \$ y ge (x + 2) / 5 \$

C) \$ y le (2x - 2) / 5 \$

D) \$ y le (2x + 2) / 5 \$

Steps 3

Solve the inequality \$ | 3x - 2 | + | 2x + 1 | < 5 \$.

A) \$ x < 6/5 \$, \$ x > 2\$ and \$ x < 4/5 \$

B) \$ x > 6/5 \$, \$ x > - 2\$ and \$ x < - 4/5 \$

C) \$ x < 6/5 \$, \$ x > 2\$ and \$ x > - 4/5 \$

D) \$ x < 6/5 \$, \$ x > - 2\$ and \$ x < - 4/5 \$

Steps 4

Solve the inequality \$\sqrt (2x + 3) - 4 > 0\$.

A) \$x > -13/2\$

B) \$x < 13/2\$

C) \$x > 13/2\$

D) \$x < -13/2\$

Steps 5

Solve the inequality \$| (2x + 3)/(x - 4) | ge 1 \$.

A) x ≥ -7 or \$x le -1/3\$

B) x ≥ 7 or \$x le 1/3\$

C) x ≥ 7 or \$xle -1/3\$

D) \$-7 le x le 1/3\$


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