Lesson Example Discussion Quiz: Class Homework |
Example |
Title: Area of Triangle |
Grade: 1300-a Lesson: S3-L2 |
Explanation: Hello Students, time to learn examples. Let us take turns and read each example. Explain each step. Pay special attention to steps and pictures and communicate in your own words. |
Examples:
Find the area of a triangle having base is 18cm and height is 12cm.
Step 1a
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Given height(h) = 12cm Base of a triangle(b) = 18cm Therefore, area of a triangle = \$1/2 b*h\$ ⇒ \$(18\times12)/2\$ ⇒ \$216/2\$ ⇒ \$108\$sq.cm |
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Explanation: If the height of a triangle is 12cm, and the base is 18cm, the area of the triangle is 108 sq.cm as calculated using the formula: \$1/2 bh\$. |
Find the area of an equilateral triangle of side 12 cm. \$\sqrt 3 = 1.73\$.
Step 2a
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Given the side of a triangle = 12cm Area of an equilateral triangle = \$\sqrt 3/4\$ a² square units ⇒ \$\sqrt 3/4 \times 12 \times 12\$ ⇒ \$\sqrt 3/4 \times 144\$ ⇒ \$\sqrt 3 * \cancel144^36/\cancel4^1\$ ⇒ \$1.73 \times 36\$ ⇒ 62.28 cm² |
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Explanation: If the side of an equilateral triangle is 12cm, then the area of an equilateral triangle is 62.28 cm². |
Find the height of a triangle whose area is 420 cm² and base is 60 cm.
Step 3a
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The given area of a triangle(a) = 420 cm² The base of a triangle(b) = 60 cm Therefore, height of a triangle = \$(2 \times a)/b\$ ⇒ \$(2 \times 420)/60\$ ⇒ 14cm |
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Explanation: If the area of a triangle is 420 cm², and the base of a triangle is 60 cm, the height of a triangle is 14cm as calculated using the formula \$(2\times a/b)\$. |
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