Lesson Topics Discussion Quiz: Class Homework |
Steps-3 |
Title: Quadratic-Equations and Factors |
Grade Lesson s6-l1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Solve the quadratic equation \$2x^2 + 5x - 3 = 0\$. |
|
2 |
Step |
The given equation is |
\$2x^2 + 5x - 3 = 0\$ |
3 |
Formula |
The quadratic formula states that for an equation in the form \$ax^2 + bx + c = 0\$, the solutions for x can be found using the formula: \$x = (-b ± \sqrt (b^2 - 4ac)) / (2a)\$. |
|
4 |
Hint |
Here the a = 2, b = 5 and c = -3. |
|
5 |
Step |
Plug the values in the fromula: |
\$x = (-5 ± \sqrt (5^2 - 4 \times 2 \times -3)) / (2 \times 2)\$ \$x = (-5 ± 7) / 4\$ |
6 |
Step |
This gives us two possible solutions: |
\$x_1 = (-5 + 7) / 4, x_2 = (-5 - 7) / 4\$ |
7 |
Step |
When we take the Positive and negative square roots then after simplified |
\$x_1 = (-5 + 7) / 4\$ (or) \$x_2 = (-5 - 7) / 4\$ \$1/2\$ = 0.5 (or) x = -3 |
8 |
Solution |
Therefore, the solutions to the quadratic equation \$2x^2 + 5x - 3 = 0\$ are x = 0.5 and x = -3. |
|
9 |
Sumup |
Please summarize Problem, Clue, Hint, Formula, Steps and Solution |
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Choices |
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10 |
Choice-A |
Both solutions to the quadratic equation are accurate and acceptable |
Correct \$x = 1/2 \$ or x = - 3 |
11 |
Choice-B |
The solutions for the quadratic equations are not precise |
Wrong \$x = 3/2 \$ or x = - 4 |
12 |
Choice-C |
The solutions for the quadratic equations are not precise |
Wrong \$x = 2/3 \$ or x = 3 |
13 |
Choice-D |
The solutions for the quadratic equations are not precise |
Wrong x = - 0.6 or x = 4 |
14 |
Answer |
Option |
A |
15 |
Sumup |
Please summarize choices |
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