Lesson Topics Discussion Quiz: Class Homework |
Steps-5 |
Title: Trigonometry function ( sine, cosine, tangent) |
Grade Lesson s5-l1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Evaluate the following expression: \$ sin(pi/3) cos(pi/6) + cos(pi/3) sin(pi/6) \$. |
|
2 |
Step |
Let’s evaluate the given expression step by step: |
\$ sin(pi/3) cos(pi/6) + cos(pi/3) sin(pi/6) \$ |
3 |
Step |
First, let’s use the trigonometric identities: |
\$ sin(pi/3) = \sqrt3 / 2 \$ \$ cos(pi/3) = 1/2 \$ \$ sin(pi/6) = 1/2 \$ \$ cos(pi/6) = \sqrt3 / 2 \$ |
4 |
Hint |
Now substitute these values into the expression: |
\$ \sqrt3 / 2 \times \sqrt3 / 2 + 1/2 \times 1/2 \$ |
5 |
Step |
Simplify further: |
\$ 3/4 + 1/4 \$ |
6 |
Step |
Combine the terms: |
\$ 4/4 = 1 \$ |
7 |
Solution |
So, the evaluated value of the expression is 1. |
|
8 |
Sumup |
Please summarize Problem, Clue, Hint, Formula, Steps and Solution |
|
Choices |
|||
9 |
Choice-A |
This is correct because the result equals 1 after evaluation |
Correct 1 |
10 |
Choice-B |
This is incorrect because after the evaluation the result is not 1 |
Wrong \$ 1/2\$ |
11 |
Choice-C |
The evaluation yields a result other than 1, making this statement incorrect |
Wrong \$ \sqrt3/2\$ |
12 |
Choice-D |
The evaluation yields a result other than 1, thus rendering this statement incorrect |
Wrong \$ \sqrt 3\$ |
13 |
Answer |
Option |
A |
14 |
Sumup |
Please summarize choices |
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