Lesson Topics Discussion Quiz: Class Homework |
Steps-5 |
Title: Trigonometry |
Grade Lesson s5-p2 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Prove that \$4 (2 tan^(-1) (1/3) + tan^(-1) (1/7)) = (pi)\$. |
|
2 |
Step |
The given function is |
\$4 (2 tan^(-1)(1/3) + tan^(-1) (1/7)) = (pi)\$ |
3 |
Step |
Let’s start by letting: |
\$α = tan^(-1) (1/3)\$ and \$β = tan^(-1) (1/7)\$ |
4 |
Formula |
Since \$α = tan^(-1)(1/3)\$, we have \$tanα =1/3\$. |
|
5 |
Hint |
The given equation can be rewritten using α and β: 4(2α + β) = π. |
|
6 |
Formula |
Calculate tan(2α) using the double-angle formula for tangent: \$tan(2α) = tan(2α) / (1- tan^2(α))\$. |
|
7 |
Step |
Plug the values in the formula and then simplify it: |
\$tan(2α) = (2 \times 1/(3))/(1 - (1/3)^2)\$ \$ tan(2α) = (2/(3))/(1- 1/(9))\$ \$tan(2α) = (2/3)/(8/(9))\$ \$tan(2α) = 3/4\$ |
8 |
Formula |
The tangent of a sum of two angles is given by: \$tan(A + B) = (tanA + tanB)/(1 - tanA tanB)\$. |
|
9 |
Formula |
The formula is rewritten as calculate tan(2α+β) using the tangent addition: \$tan(2α + β) = (tan(2α) + tanβ)/(1 - tan(2α) tanβ)\$. |
|
10 |
Step |
Plug the values in the formula and then simplify it: |
\$tan(2α + β) = (3/(4) + 1/(7))/(1 - 3/(4) . 1/(7))\$ \$tan(2α + β) = ((21)/ (28) + 4/(28))/(1 - 3/(28))\$ \$tan(2α + β) = (25/28)/(25/28)\$ \$tan(2α + β) = 1\$ |
11 |
Step |
Since tan(2α + β )= 1 , we know: |
\$(2α + β) = tan^(-1) (1)\$ \$(2α + β) = (pi)/4\$ |
12 |
Step |
Thus, substituting back, we get: |
\$4(2α + β) = 4 \times (pi)/4 = (pi)\$ |
13 |
Solution |
Therefore, the given equation: \$4 (2 tan^(-1)(1/3) + tan^(-1) (1/7)) = (pi)\$ is proven to be true. |
|
14 |
Sumup |
Please summarize Problem, Clue, Hint, Formula, Steps and Solution |
|
Choices |
|||
15 |
Choice-A |
This is incorrect because the statement we needed to prove does not result in the value 1; it results in π |
Wrong 1 |
16 |
Choice-B |
Option B is correct because the equation \$4(2tan^(-1) (1/3) + tan^(-1) (1/7)) = π\$ is proven to be true by using the formulas |
Correct Proved |
17 |
Choice-C |
Wrong: Because the equation does not equal zero |
Wrong Zero |
18 |
Choice-D |
The "Not proved" option is incorrect because we have shown that the original equation is true using trigonometric identities and properties of the arctangent function |
Wrong Not proved |
19 |
Answer |
Option |
B |
20 |
Sumup |
Please summarize choices |
|
Copyright © 2020-2024 saibook.us Contact: info@saibook.org Version: 4.0 Built: 17-Oct-2025 12:00PM EST