Example

Title: Slope & Line Segment

Grade: 8-a Lesson: S1-L4

Explanation: The best way to understand algebra is by looking at some examples. Take turns and read each example for easy understanding.

Examples:

To find the equation of the line passing through the points (1, -2) and (4, -5)

Step 1a

First, to find the slope (m) of a line passing through two points (x1, y1) and (x2, y2) is given by: \$m = (y2 - y1) / (x2 - x1)\$

Explanation: To find the slope (m) of a line passing through two points (x1, y1) and (x2, y2), use this formula:\$m = (y2 - y1) / (x2 - x1)\$

Step 2a

Let’s plug in the coordinates of the given points (1, -2) and (4, -5): \$m = (-5 - (-2)) / (4 - 1)\$ then m= -1.

Explanation: To find the coordinates of the given points, (1, -2) and (4, -5), we can input them into the equation and determine that the slope is -1.

Step 3a

In this step, Use the point-slope form. Now that we have the slope (m = -1) and one point (1, -2), we can write the equation of the line: y − y1 = m(x − x1)

⇒y - (-2) = -1(x - 1)

Explanation: To proceed, apply the point-slope form. With the slope (m = -1) and one point (1, -2), we can formulate the equation of the line as follows: y − y1 = m(x − x1). Therefore, substituting the values, we get y - (-2) = -1(x - 1).

Step 4a

Let’s move on to the next step, where we’ll convert the equation to slope-intercept form (y = mx + b), with ""b"" representing the y-intercept.

Here’s the simplified equation: y = -x + 1 - 2.

After further simplification, we get: y = -x - 1

Explanation: Convert the equation to slope - intercept form, y = mx + b, where "b" is the y - intercept. The simplified equation is y = - x - 1.

Step 5a

So, the equation of the line passing through the points (1, -2) and (4, -5) is y = -x - 1.

Explanation: The equation for the line that passes through the coordinates (1, -2) and (4, -5) is y = -x - 1.


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